Ask question

Ask question

All categories

3 years ago

6

A liquid with a specific gravity of 2.6 and a viscosity of 2.0 cP flows through a smooth pipe of unknown diameter, resulting in

a pressure drop of 0.183 lb/in? for 1.73 mi. What is a pipe diameter in inches if the mass rate of flow is 7000 lb/h?

1 answer:

sasho [114]3 years ago

6 0

.......,.,.,.,.,.,,.,.,,.,.,.,.,.,.,.,,.,.,,.,,,.,,.,,.,.,.,.,,............,,,,,,’mmdjidvdhxxkf jkkk he in d

You might be interested in

Water flows through two smooth pipes with the same diameter and length as shown below. ipe is twice that through the first-pipe.

Alisiya [41]

Answer:

The right answer is (d)

Explanation:

The pressure drop in smooth pipes with laminar flow is determined by the resistance of the fluid to flow, which is controlled by Reynolds's number. At higher Re, higher drop. But in this case, we have no information about the speed of the fluid in each pipe, and the ipe is not related to that speed. therefore we don´t have the information to say that any of the other options are the right ones

3 0

3 years ago

Sarah and Raj take/takes me to a baseball game every year.

timofeeve [1]

Answer:

take

play

are

sits

crouches

direct

indirect

direct

direct

indirect

Explanation:

i had just taken the test

4 0

3 years ago

What is the line called that has the red arrow pointing to it in the attached picture?

Simora [160]

Answer:

csvadbvns egv,ekrhvybge e yrbge ngeeeeerhjyk4 r5y erhyniner mbrltjhnprihmb fghurijmb fm nbjrkfb

Explanation:

8 0

3 years ago

A BOD test is to be run on a sample of wastewater that has a five-day BOD of 230 mg/L. If the initial DO of a mix of distilled w

Alexxandr [17]

Answer:

Distribution factor P = =38.33

V = 7.826 ml

Explanation:

given details:

BOD =230 mg/l

DO inital = 8.0mg/l

DO final = 2.0mg/l

we know

BOD = [DO inital -DO final] * distribution factor

230 = [8 - 2] D.F

Distribution factor P $= \frac{230}{6}$

Distribution factor P = =38.33

THE RANGE OF WASTE WATER VOLUME IN 300 ml bottle is

distribution factor $= \frac{300}{V}$

$V = \frac{300}{38.33}$

V = 7.826 ml

6 0

3 years ago

A satellite at a distance of 36,000 km from an earth station radiates a power of 10 W from an

notsponge [240]

This an example solved please follow up with they photo I sent ok

4 0

3 years ago