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Aleksandr [31]
3 years ago
7

In the parts that follow select whether the number presented in statement A is greater than, less than, or equal to the number p

resented in statement B.
1. Statement A: 2.567 km, to two significant figures.
Statement B: 2.567 km, to three significant figures.
Determine the correct relationship between the statements.
A. Statement A is greater than Statement B.
B. Statement A is less than Statement B.
C. Statement A is equal to Statement B.
2. Statement A: (2.567 km+ 3.146 km), to two significant figures.
Statement B: (2.567 km, to two significant figures) + (3.146 km, to two significant figures).
Determine the correct relationship between the statements.
A. Statement A is greater than Statement B.
B. Statement A is less than Statement B.
C. Statement A is equal to Statement B.
3. Statement A: Area of a rectangle with measured length = 2.536 m and width = 1.4 m.
Statement B: Area of a rectangle with measured length = 2.536 m and width = 1.41 m.
Determine the correct relationship between the statements.
A. Statement A is greater than Statement B.
B. Statement A is less than Statement B.
C. Statement A is equal to Statement B.
Physics
1 answer:
OleMash [197]3 years ago
7 0

Answer:

1)   A> B, 2)  A = B,  3)    A> B

Explanation:

When a figure is given the number of significant figures to determine the precision or uncertainty the number

1) the uncertainty in the number with three significant figures is less than the number with two significant figures

statement A 2.6

statement B 2.57

        A> B

2) decalration A

         2,567 + 3,146 = 5,713

with two figures it remains

             5.7

statement B

         2.6 + 3.1 = 5.7

 A = B

3) for the product the result is with the number that has the least significant figures

statement A

rectangles area

   2.536 * 1.4 = 3.6

  statement B

    2.536 * 1.41 = 3.58

          A> B

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calculate minimum number of incident photons per area and of the minimum dose needed to visualize an object of 1 mm squared usin
Lynna [10]

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Explanation:

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thickness = 10^-3

contrast = 1%

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number of incident photons

solution

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3 0
3 years ago
Una persona de 80kg intenta bajar de peso subiendo una montaña para quemar el equilante a una rebanada de pastel de chocolate (7
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Answer:

Explanation:

An 80kg person tries to lose weight by climbing a mountain to burn the equivalent of a large slice of a rich chocolate cake (700kcl). How high should you climb?

Given that,

A person of mass

M = 80kg

The person is climbing a stair case and he burn an energy of 700 kcl

We know that 1kcl = 4184J

Then, 700kcl = 700 × 4184J

700kcl = 2.9288 × 10^6 J

We want to find height of stairs the person will climb when he Loss 700kcl. The energy he burns will be converted to the potential energy

P.E is calculated using

P.E = mgh

Where

m is mass in kg

g is gravitational constant g = 9.81m/s2

h is the height of stairs he climb in metre

Then,

P.E = energy burn

mgh = 700kcl

80 × 9.81 × h = 2.9288 × 10^6

h = (2.9288 × 10^6) / (80 × 9.81)

h = 3731.91m

So, the person will climb 3731.91m before he losses 700kcl

In espanyol

Dado que,

Una persona de masa

M = 80 kg

La persona está subiendo una escalera y quema una energía de 700 kcl.

Sabemos que 1kcl = 4184J

Entonces, 700kcl = 700 × 4184J

700kcl = 2.9288 × 10 ^ 6 J

Queremos encontrar la altura de las escaleras que la persona subirá cuando pierda 700kcl. La energía que quema se convertirá en energía potencial.

P.E se calcula utilizando

P.E = mgh

Dónde

m es masa en kg

g es constante gravitacional g = 9.81m / s2

h es la altura de las escaleras que sube en metros

Entonces,

P.E = quema de energía

mgh = 700kcl

80 × 9.81 × h = 2.9288 × 10 ^ 6

h = (2.9288 × 10 ^ 6) / (80 × 9.81)

h = 3731.91m

Entonces, la persona subirá 3731.91m antes de perder 700kcl

5 0
3 years ago
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