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melamori03 [73]
3 years ago
12

The mass of 2.50 moles of calcium fluoride is ____ grams

Chemistry
2 answers:
lapo4ka [179]3 years ago
8 0

Answer:

195.187016

Explanation:

Vesna [10]3 years ago
3 0

Answer:

195.187016

Explanation:

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5. Which organelle, found in plant and
Annette [7]
The answer would be VACUOLES
4 0
3 years ago
A mixture containing initially 3.90 mole of NO(g) and 0.88 mole of CO2(g) was allowed to react in a flask of volume 1.00 L at a
Ymorist [56]

Answer:

Equilibrium constant Kc for the reaction will be 1.722

Explanation:

O2(g)+NO(g)→CO(g)+ NO2(g)

0.88    3.9        ---         ---

0.88x   3.9-x     x           x

GIVEN:

0.88X-X= 0.11

⇒ X=0.77

CO2(g)+NO(g) → CO(g) + NO2(g)

0.88       3.9         ---          ---

0.88-x    3.9-x      x            x

=              3.13       0.77      0.77

=0.11

Kc = \frac{[CO] *[NO2]} {[CO2]*[NO]}

     ={{0.77}×0.77÷{{0.11×3.13}}

     = 1.722

6 0
3 years ago
A fusion reaction takes place between carbon and another element. Neutrons are released, and a different element is formed. The
sdas [7]

Answer:

Dependent on the element that reacted with carbon

Explanation:

Nuclear fusion is the combination of small atomic nuclei into larger ones usually accompanied with the release of a large amount of energy.

From the problem stated, carbon fuses with another atom. The combined atom would have more nuclear particles in terms of protons and neutrons than the combining atoms. This will eventually make it weigh more than carbon and the atom it combines with. The resulting weight will depend on the combining atoms eventually.

7 0
3 years ago
Read 2 more answers
What is the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 22.3
snow_lady [41]

The free energy change(Gibbs free energy-ΔG)=-8.698 kJ/mol

<h3>Further explanation</h3>

Given

Ratio of the concentrations of the products to the concentrations of the reactants is 22.3

Temperature = 37 C = 310 K

ΔG°=-16.7 kJ/mol

Required

the free energy change

Solution

Ratio of the concentration : equilbrium constant = K = 22.3

We can use Gibbs free energy :

ΔG = ΔG°+ RT ln K

R=8.314 .10⁻³ kJ/mol K

\tt \Delta G=-16.7~kJ/mol+8.314.10^{-3}\times 310\times ln~22.3\\\\\Delta G=-8.698~kJ/mol

8 0
3 years ago
I need help! Please give me an answer
Zepler [3.9K]
You need to show us what you’re talking about first
6 0
2 years ago
Read 2 more answers
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