p = latm
t = 273.15K
R= 0.08206 L atm mol K
75.0g02
16.00 (O₂) = 4.6875mol mol
9
Ideal gas law: PV = nRT, solve for volume: V = nRT P
V =
4.6875mol 0.08206 L-atm mol. K · 273.15K
V = 105L
latm
Answer:
liquid
Explanation:
the state of matter is liquid
Good the equation is balanced already
<h2>Answer:</h2>
He is right that the energy of vaporization of 47 g of water s 106222 j.
<h3>Explanation:</h3>
Enthalpy of vaporization or heat of vaporization is the amount of energy which is used to transform one mole of liquid into gas.
In case of water it is 40.65 KJ/mol. And 18 g of water is equal to one mole.
It means for vaporizing 18 g, 40.65 kJ energy is needed.
So for energy 47 g of water = 47/18 * 40.65 = 106.1 KJ
Hence the student is right about the energy of vaporization of 47 g of water.
yes because the
0。5 that's left may stop the batter from over flowing