Answer: Kc= 4.653
Explanation:
From The equation of reaction
CO(g)+2H2(g)⇌CH3OH(g)
From the question
[CH3OH] =0.0679 moles
[CO]= 0.160moles
[H2]= 0.302
Kc = [CH3OH]/[CO] [H2]^2
Kc=[0.069]/[0.16]×[0.302]^2
Kc= 4.653
Answer:
1.53x10^22 atoms of Au
Explanation:
To find the atoms of gold we need first, to convert the mass of gold to moles using molar mass of gold (196.97g/mol). Then, these moles must be converted to number of atoms based on definition of moles (1 mole = 6.022x10²³ atoms).
<em>Moles Au:</em>
5.00g Au * (1mol / 196.97g) = 0.0254 moles of Au
<em>Atoms of Au:</em>
0.0254 moles * (6.022x10²³ atoms / 1 mole) =
<h3>1.53x10^22 atoms of Au</h3>
Answer:
8.33 atm
Explanation:
Xe is 5 out of (4+5) or 5 / 9 ths of the gas present
5/9 * 15 atm = 8.33 atm
Explanation:
First, let's convert 481 mmHg to atm:
1 atm --- 760 mmHg
x atm --- 481 mmHg
x = 0.63 atm
mmHg to Torr:
1 mmHg ---- 1 Torr
481 mmHg --- 481 Torr
481 Torr
mmHg to inHg
1 mmHg ---- 0.039 inHg
481 mmHg ---- y inHg
y = 18.8 inHg
mmHg to Pa
1 mmHg --- 133.322 Pa
481 mmHg ---- z
z = 64,128 Pa
Answer:
0.63 atm
481 Torr
18.8 inHg
64,128 Pa
Answer:
Ratio of [CO₃²⁻] / [H₂CO₃] is 1.0x10⁻⁸
Explanation:
Based on the equilibriums:
H₂CO₃ ⇄ H⁺ + HCO₃⁻ Ka1 = 4.3x10⁻⁷
HCO₃⁻ ⇄ H⁺ + CO₃²⁻ Ka2 = 4.8x10⁻¹¹
The sum of both equilibriums is:
H₂CO₃ ⇄ 2 H⁺ + CO₃²⁻ K' = 4.3x10⁻⁷*4.8x10⁻¹¹ = 2.064x10⁻¹⁷
Where K' is defined as:
K' = 2.064x10⁻¹⁷ = [H⁺]² [CO₃²⁻] / [H₂CO₃]
If concentration of H⁺ is 4.5x10⁻⁵M:
K' = 2.064x10⁻¹⁷ = [4.5x10⁻⁵]² [CO₃²⁻] / [H₂CO₃]
1.0x10⁻⁸ = [CO₃²⁻] / [H₂CO₃]
Thus, <em>ratio of [CO₃²⁻] / [H₂CO₃] is 1.0x10⁻⁸</em>