For this problem, we use Graham's Effusion Law to find out the rate of effusion of chlorine gas. The formula is as follows:
R₁/R₂ = √(M₂/M₁)
Let 1 be N₂ while 2 be Cl₂
255/R₂ = √(28/70.8)
Solving for R₂,
R₂ = 405.5 s
<em>Thus, it would take 405.5 s to effuse chlorine gas.</em>
Answer:
Q = 1360.248 j
Explanation:
Given data:
Mass of brass = 298.3 g
Initial temperature = 30.0°C
Final temperature = 150°C
Specific heat capacity of brass = 0.038 J/g.°C
Heat absorbed = ?
SOLUTION:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
ΔT = 150°C - 30.0°C
ΔT = 120°C
Q = 298.3 g × 0.038 J/g.°C × 120°C
Q = 1360.248 j
Answer:
f(x) = 6x²-3
f(x) = 0
6x²-3 = 0
6x² = 3
x² = 3/6
x² = 1/2
x = 1/√2 , -1/√2
Roots of f(x) = 1/√2 , -1/√2
Verification = (i) 6(1/√2)² - 3
= 6(1/2) - 3
= 3-3
= 0
(ii) 6(-1/√2)² - 3
= 6(1/2) - 3
= 3-3
= 0
