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mr Goodwill [35]
2 years ago
9

How much O2 could be produced from 2.59 g of KO2 and 4.56 g of CO2?

Chemistry
1 answer:
Anna71 [15]2 years ago
4 0

Answer:

This is a limiting reagent problem. the way to figure it out is to do the stoichiometry for each amount given, calculating the amount of Oxygen produced. The smallest amount is the answer because that reactant "ran out".

for KO2

2.49g KO2 x 1 mole KO2 x 3 mole O2 x 32.00 g O2 = 0.841 g O2

71.10 g KO2 4 mole KO2 1 mole O2

for CO2

4.44g CO2 x 1 mole CO2 x 3 mole O2 x 32.00g O2 = 4.84 g O2

44.01 g CO2 2 mole CO2 1 mole O2

Therefore the answer is 0.841g O2 since it is the smallest amount produced meaning KO2 is the limiting reagent.

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How many of the following are found in 15.0 kmol of xylene (C8H10)? (a) kg C8H10; (b) mol C8H10; (c) lb-mole C8H10; (d) mol (g-a
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a) 1592.4 kg C8H10

b) 15*10³ mol C8H10

c) 33.1 lb-mole

d) 1.2 *10^5 mol C

e)  1.5 * 10^5 mol H

f)  1.44 * 10^6 grams C

g) 1.52 * 10^5 grams H

h) 9.03*10^27 molecules C8H10

Explanation:

Step 1: Data given

Number of moles C8H10 = 15.0 kmol =15000 moles

Molar mass of C8H10 = 106.16 g/mol

Step 2: Calculate mass C8H10

Mass C8H10 = moles C8H10 * molar mass C8H10

Mass C8H10 = 15000 * 106.16 g/mol

Mass C8H10 = 1592400 grams = 1592.4 kg

Step 3: Calculate moles C8H10

15.0 kmol = 15*10³ mol C8H10

Step 4: Calculate lb-mol

15.0 kmol = 33.1 lb-mole

Step 5: Calculate moles of C

For 1 mol C8H10 we have 8 moles of C

For 15*10³ mol C8H10 we have 8* 15*10³  =1.2 *10^5 mol C

Step 6: Calculate moles H

For 1 mol C8H10 we have 10 moles of H

For 15*10³ mol C8H10 we have 10* 15*10³  = 1.5 * 10^5 mol H

Step 7: Calculate mass of C

Mass C = moles C * molar mass C

Mass C = 1.2 *10^5 mol C * 12 g/mol

Mass C = 1.44 * 10^6 grams

Step 8: Calculate mass of H

Mass H = moles H * molar mass H

Mass H = 1.5 *10^5 mol H * 1.01 g/mol

Mass C = 1.52 * 10^5 grams

Step 9: Calculate molecules of C8H10

Number of molecules = number of moles * number of Avogadro

Number of molecules =  15*10³ mol C8H10 * 6.022*10^23

Number of molecules = 9.03*10^27 molecules

8 0
2 years ago
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