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Misha Larkins [42]
3 years ago
7

While driving his 600-kg ultra-compact electric car, a distracted driver starts crossing a drawbridge. Not realizing that the dr

awbridge is about to open, he ends up in the river below with his car. Fortunately the car stayed afloat for a while and he is able to escape before it starts sinking. (a) If the volume of the interior is 2.0 m3, what fraction of the car is immersed while it floats? (b) Eventually, water starts to leak in and gradually fills the car. What is the mass of the water that entered the car when the car starts to sinks? Density of water is 1000 kg/m3.
Physics
1 answer:
stellarik [79]3 years ago
4 0

Answer:

Explanation:

a )

weight of car = 600 kg .

According to Archimedes principle , for free floatation ,

weight of car = weight of displaced water

600 x 9.8 = v x 10³ x 9.8 , v is volume of water displaced and 10³ kg/ m³ is density of water.

v = .6 m³

required fraction

= .6 / 2

= .3

b )

Let mass of water entering before the start of sinking of car .

mass of maximum displaced volume of water by car = 2 x 10³m³.

(600 + m ) x g = 2 x 10³ x g         [   10³ is density of water    ]

600 + m = 2000

m = 1400 kg .  

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Answer:

1.4007\times 10^{-8}\ N

1.50075\times 10^{-6}\ N

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Explanation:

m_1 = Mass of baby = 3 kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Distance between objects

Gravitational force of attraction is given by

F=\dfrac{Gm_1m_2}{r^2}\\\Rightarrow F=\dfrac{6.67\times 10^{-11}\times 70\times 3}{1^2}\\\Rightarrow F=1.4007\times 10^{-8}\ N

The force between baby and obstetrician is 1.4007\times 10^{-8}\ N

F=\dfrac{6.67\times 10^{-11}\times 3\times 2.7\times 10^{27}}{(6\times 10^{11})^2}\\\Rightarrow F=1.50075\times 10^{-6}\ N

The force between the baby and Jupiter is 1.50075\times 10^{-6}\ N

F=\dfrac{6.67\times 10^{-11}\times 3\times 2.7\times 10^{27}}{(9\times 10^{11})^2}\\\Rightarrow F=0.000000667\ N

The force between the baby and Jupiter is 0.000000667\ N

7 0
3 years ago
A power lifter performs a dead lift, raising a barbell with a mass of 305 kg to a height of 0.42 m above the ground, giving the
Ann [662]

Answer:

Explanation:

Before it hits the ground:

The initial potential energy = the final potential energy + the kinetic energy

mgH = mgh + 1/2 mv²

gH = gh + 1/2 v²

v = √(2g (H - h))

v = √(2 * 9.81 m/s² * (0.42 m - 0.21 m))

v ≈ 2.0 m/s

When it hits the ground:

Initial potential energy = final kinetic energy

mgH = 1/2 mv²

v = √(2gH)

v = √(2 * 9.81 m/s² * 0.42 m)

v ≈ 2.9 m/s

Using a kinematic equation to check our answer:

v² = v₀² + 2a(x - x₀)

v² = (0 m/s)² + 2(9.8 m/s²)(0.42 m)

v ≈ 2.9 m/s

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3 years ago
A capacitor is made from two hollow, coaxial, iron cylinders, one inside the other. The inner cylinder is negatively charged and
notsponge [240]

Answer: 1) 17.65 * 10^-12 C/V; 2) 0.68 V

Explanation: In order to calculate the capacitance of one cylinder capacitor we have to use the following expression:

C=\frac{2\pi \epsilon o L}{ln (b/a)} where and b are the inner and outer radius of teh cylinder, respectively. L is length of the cylinder.

Finally we also kwn that C=Q/ΔV

then we have

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A worker on the roof of a house drops his 0.46 kg hammer, which slides down the roof at constant speed of 9.88 m/s. The roof mak
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Answer:

The horizontal distance travelled in that time lapse is 12.94 m

Explanation:

In order to solve this problem, we'll need:

  1. The horizontal speed
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At the lowest point of the roof, the hammer has a 9.88 m/s speed that makes an angle of 27° with the horizontal, so we can calculate the horizontal and vertical speed with trigonometry. If we take right as x positive and down as y positive we get

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Now, we make two movement equation as we have a URM (no acceleration) in x and an ARM (gravity as acceleration) in y. We will wisely pick the lowest point of the roof as the origin of coordinates

x(t)=8.8 m/s *t

y(t)=4.49m/s*t+\frac{1}{2}*9.8m/s^{2}*t^{2}

Now we calculate the time the hammer takes to get to the floor

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Now, we keep the positive time result and calculate the horizontal distance travelled

x(1.47s)=8.8m/s*1.47s=12.94m

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