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Korvikt [17]
3 years ago
7

How much kinetic energy does a 1500 kg car have if it’s moving at 15 m/s

Physics
1 answer:
Tresset [83]3 years ago
6 0

Answer:

Mass of car m = 1500 kg

velocity v = 15 m/s

kinetic energy = ½ mv2

= ½ x 1500 x (15)2    

= 1687501   kg m2 /s2

  = 168750J

Explanation:

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Why does the solar system consist of small planets orbiting close to sun and larger on more distant
ahrayia [7]

Answer:

The inner planets are smaller and rockier

Explanation:

Astronomers divide the planets into two groups in Solar system,  the  inner planets and outer planets. The inner planets are smaller and rockier and it is closer to the sun.  The outer planets are larger , further far away and made of gas

The inner planets are Mercury, Venus , Earth and Mars.  The outer planets Jupiter , Saturn , Uranus and Neptune comes after an  asteroid belt. In some other planetary systems the gas are close to the sun.

particles in a disk of gas and dust will form Planets.  If they orbit the star they are colliding and sticking.  The stars wind blows away their gases . So the nearest planets to starts are rockier.

6 0
3 years ago
A rock weighing 98 newtons is pushed off the edge of a bridge 50 meters above the ground. What was the kinetic energy of the roc
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2,450 Joules,  kinetic energy is 1/2 mass x velocity squared.
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3 years ago
Determine the field strength, E, experienced by a test charge, q, if a charge of 7.0 × 10-5 coulombs is placed on q and a force
kkurt [141]
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q=7.0^10-5 coulombs
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7 0
3 years ago
Read 2 more answers
A 320 g air track cart traveling at 1.25 m/s collides with a stationary 270 g cart. What is the speed of the 270 g cart after th
Nutka1998 [239]

Answer:

The speed of the 270g cart after the collision is 0.68m/s

Explanation:

Mass of air track cart (m1) = 320g

Initial velocity (u1) = 1.25m/s

Mass of stationary cart (m2) = 270g

Velocity after collision (V) = m1u1/(m1+m2) = 320×1.25/(320+270) = 400/590 = 0.68m/s

7 0
3 years ago
If the acceleration of a motorboat is 4.0 m/s2, and the motorboat starts from rest, what is its velocity after 6.0 s?
umka2103 [35]

Answer:

The velocity of the motorboat after 6s is 24 m/s.

Explanation:

Given;

acceleration of the motorboat, a = 4.0 m/s²

initial velocity of the motorboat, u = 0

time of motion of the motorboat = 6s

Apply the following kinematic equation to determine the velocity of the motorboat after 6 ;

v = u + at

v = 0 + (4 x 6)

v = 24 m/s

Therefore, the velocity of the motorboat after 6s is 24 m/s.

6 0
3 years ago
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