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3 years ago

11

What is surface water or runoff?

1 answer:

Rudik [331]3 years ago

7 0

Water that gathers on the surface of the ground is surface water
movement of landwater to the oceans is runoff

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Which physical property is used to test the purity of metal ?

dimulka [17.4K]

The physical and chemical properties of metal can differ between the elements but if we try and generalize.

Physical properties are that they are hard, dense, shiny, malleable (can be bent), ductile (can be pulled into wires), a good conductor of heat and have high melting points meaning that they are solid at room temperature

Their chemical properties include being good electrical conductors, they make metallic bonds (ionic bonds with non-metals) and their atoms are arranged in a lattice. They release hydrogen when reacted with acids and are usually cations (positive ions).

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3 years ago

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3 years ago

A fisherman sees his boat moving up and down, owing to waves on the water. It takes 2.5 s for the boat to travel from its highes

nata0808 [166]

Answer:

The waves are traveling in a speed of

v=1.20 m/s

Explanation:

The fisherman see a wave at 6m apart so that's the wavelength

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$t=2*2.5s=5s$

The velocity of the waves is describe by:

$v=f*L$

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4 years ago

Where could you most likely observe a volcano?

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I'm thinking the answer is going to b B

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3 years ago

Joey, whose mass is m = 36 kg, stands at rest at the outer edge of a frictionless merry-go-round with the mass M = 300 kg and th

Evgen [1.6K]

Answer:

$\omega=0.24\ rad.s^{-1}$

Explanation:

Given:

mass of person, $m=36\ kg$

mass of merry go-round, $M=300\ kg$

radius of merry go-round, $R=2\ m$

velocity of the person running, $v=4\ m.s^{-1}$

<u>We consider merry go-round as a ring:</u>

Now the moment of inertial of the ring is given as,

$I=M.R^2$

$I=300\times 2^2$

$I=1200\ kg.m^{-2}$

<u>Moment of inertia of the person considering as a point mass:</u>

$I_p=m.R^2$

$I_p=36\times 2^2$

$I_p=144\ kg.m^2$

<u>Now according to the conservation of angular momentum:</u>

$I.\omega=I_p.\omega_p$

where:

$\omega =$ angular velocity of the merry-go-round

$\omega_p=$ angular velocity of the person running

$1200\times \omega=144\times \frac{v}{R}$

$\omega=\frac{144}{1200} \times \frac{4}{2}$

$\omega=0.24\ rad.s^{-1}$

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3 years ago

Read 2 more answers