Question

With what minimum speed must you toss a 110 g ball straight up to just touch the 11-m-high roof of the gymnasium if you release the ball 1.3 m above the ground?

Answer 1

Answer:

 v = 13.79 m/s

Explanation:

given,

mass of ball = 110 g

height = 11 m

ball is released from = 1.3 m

minimum speed = ?

using conservation of energy

Potential energy is conserved in the form of kinetic energy

$P E =KE$

$m g h= \dfrac{1}{2}mv^2$

$v^2 = 2 g h$

$v=\sqrt{2 g h}$

$v=\sqrt{2\times 9.8 \times (11-1.3)}$

$v=\sqrt{2\times 9.8 \times 9.7}$

$v=\sqrt{190.12}$

       v = 13.79 m/s