Ask question

Ask question

All categories

3 years ago

14

With what minimum speed must you toss a 110 g ball straight up to just touch the 11-m-high roof of the gymnasium if you release

the ball 1.3 m above the ground?

1 answer:

Sholpan [36]3 years ago

7 0

Answer:

v = 13.79 m/s

Explanation:

given,

mass of ball = 110 g

height = 11 m

ball is released from = 1.3 m

minimum speed = ?

using conservation of energy

Potential energy is conserved in the form of kinetic energy

$P E =KE$

$m g h= \dfrac{1}{2}mv^2$

$v^2 = 2 g h$

$v=\sqrt{2 g h}$

$v=\sqrt{2\times 9.8 \times (11-1.3)}$

$v=\sqrt{2\times 9.8 \times 9.7}$

$v=\sqrt{190.12}$

v = 13.79 m/s

You might be interested in

Using energy considerations and assuming negligible air resistance, show that a rock thrown from a bridge 23.5 m above water wit

Elodia [21]

As stated in the statement, we will apply energy conservation to solve this problem.

From this concept we know that the kinetic energy gained is equivalent to the potential energy lost and vice versa. Mathematically said equilibrium can be expressed as

$\Delta KE = \Delta PE$

$\frac{1}{2}mv_f^2-\frac{1}{2} mv_0^2 = mgh_2-mgh_1$

Where,

m = mass

$v_{f,i}$ = initial and final velocity

g = Gravity

h = height

As the mass is tHe same and the final height is zero we have that the expression is now:

$\frac{1}{2}v_f^2-\frac{1}{2} v_0^2 = gh_2$

$\frac{1}{2} (v_f^2-v_0^2) = gh_2$

$(v_f^2-v_0^2) = 2gh_2$

$v_f = \sqrt{2gh_2+v_0^2}$

$v_f = \sqrt{2(9.8)(23.5)+13.6^2}$

$v_f = 25.4m/s$

7 0

3 years ago

What do understand by the efficiency of a machine? By using a block and tackel a man can raise a load of 720 N by an effort of 1

motikmotik

Answer:

Efficiency of a machine is how well the machine works and what the machine is capable of doing.

Mechanical advantage=Load/Effort.

720/180=4

6 0

3 years ago

A maple tree seed fell 180 centimeters straight toward the ground at a constant velocity. It moved that distance in 1.5seconds.

denis23 [38]

Answer: 1.2 m/s

Explanation:

Velocity $V$ is defined as the variation of position of an object or body in time. So, if we know the distance the seed traveled and the time, we can calculate its velocity:

$V=\frac{d}{t}$

Where:

$d=180 cm \frac{1 m}{100 cm}=1.8 m$ is the distance the maple seed traveled

$t=1.5 s$ is the time

Then:

$V=\frac{1.8 m}{1.5 s}$

$V=1.2 m/s$ This is the seed's velocity

7 0

3 years ago

What is an Atwood Machine?

Lady_Fox [76]

The best answer is letter (A) a double pulley system. Atwood Machine is normally used as a measurement in balancing to object to verify the mechanical law of motion with constant acceleration.

6 0

3 years ago

What happens to the gravitational force between two objects if:

rewona [7]

Answer:

A. The force of attraction will also increase i.e double.

B. The force of attraction will increase by a multiple of 4.

C. The force of attraction will decrease by a factor of 4

Explanation:

We'll begin by writing the formula for calculating the gravitational force between two objects. This is given below:

F = GM₁M₂/r²

Where:

F: is the force of attraction between the two objects.

G: is the gravitational constant.

M₁ and M₂: are the masses of the two objects.

r: is the distance between two objects.

F = GM₁M₂/r²

From the formula, we can say that:

The force (F) of the attraction between the two objects is directly proportional to the masses (M₁ and M₂) of the objects and inversely proportional to the square of the distance between (r) the two objects.

A. Determination of the force of attraction when the mass of one is doubled.

Since the force (F) is directly proportional to the the masses (M₁ and M₂) of the objects, if the mass of one is double, the force of attraction will also increase i.e double.

B. Determination of the force of attraction when the masses of both is doubled.

Since the force (F) is directly proportional to the the masses (M₁ and M₂) of the objects, if the masses of both is double, the force of attraction will also increase by a multiple of 4.

C. Determination of the force of attraction between the distance between them is doubled.

Since the force (F) of the attraction between the two objects is inversely proportional to the square of the distance between (r) the two objects. If the distance between them is doubled, the force of attraction will decrease by a factor of 4

6 0

3 years ago