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3 years ago

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To properly operate the laboratory thermometer Group of answer choices it needs to be shaken but make sure you have enough room

to shake it safely there is no need to shake it before measurement always shake it before measurement

1 answer:

ruslelena [56]3 years ago

5 0

Answer:

it needs to be shaken but make sure you have enough room to shake it safely

Explanation:

To properly operate the laboratory thermometer it needs to be shaken but make sure you have enough room to shake it safely. This done because there is a small bend in the mercury channel of a clinical thermometer that uses mercury. You must shake the thermometer to get the mercury from a previous reading from the thermometer back into the bulb for taking new reading. The bend prevents flow back into the tube so that one can comfortably take reading.

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A single loop of nickel wire, lying flat in a plane, has an area of 7.40 cm^2 and a resistance of 2.40 Ω. A uniform magnetic fie

ale4655 [162]

Explanation:

It is given that,

Area of nickel wire, $A=7.4\ cm^2=7.4\times 10^{-4}\ m^2$

Resistance of the wire, R = 2.4 ohms

Initial value of magnetic field, $B_1=0.5\ T$

Final magnetic field, $B_2=3\ T$

Time, t = 1.12 s

Let I is the induced current in the loop of wire over this time. Te emf induced in the wire is given by Faraday's law as :

$\epsilon=-\dfrac{d\phi}{dt}$

$\epsilon=-\dfrac{d(BA)}{dt}$

$\epsilon=-A\dfrac{d(B)}{dt}$

$\epsilon=-A\dfrac{B_2-B_1}{t}$

$\epsilon=-7.4\times 10^{-4}\times \dfrac{3-0.5}{1.12}$

$\epsilon=1.65\times 10^{-3}\ V$

Induced current in the loop of wire is given by :

$I=\dfrac{\epsilon}{R}$

$I=\dfrac{1.65\times 10^{-3}}{2.4}$

$I=6.87\times 10^{-4}\ A$

So, the induced current in the loop of wire over this time is $6.87\times 10^{-4}\ A$ . Hence, this is the required solution.

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Why a paperclip does NOT float?

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An atom of potassium has an atomic mass of 39 amu and an atomic number of 19. It therefore has ______ neutrons in its nucleus.

FromTheMoon [43]

A=atomic mass
Z=atomic number (nº of protons).
N=neutons.

A=Z+N

Data:
A=39
Z=19

A=Z+N
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Fan can accelerate from the starting blocks to running 11m/s down the track in 5 seconds. What is her acceleration?

Firdavs [7]

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3 years ago

Please help thank you

Margarita [4]

Answer:

$\theta \approx 59.036^{\circ}$ , $T_{2} \approx 23.324\,N$

Explanation:

First we build the Free Body Diagram (please see first image for further details) associated with the mass, we notice that system consist of a three forces that form a right triangle (please see second image for further details): (i) The weight of the mass, (ii) two tensions.

The requested tension and angle can be found by the following trigonometrical and geometrical expressions:

$\theta = \tan^{-1} \frac{W}{T_{2}}$ (1)

$T_{1} = \sqrt{W^{2}+T_{2}^{2}}$ (2)

Where:

$W$ - Weight of the mass, measured in newtons.

$T_{1}$ , $T_{2}$ - Tensions from the mass, measured in newtons.

If we know that $W = 20\,N$ and $T_{2} = 12\,N$ , then the requested values are, respectively:

$\theta = \tan^{-1} \frac{20\,N}{12\,N}$

$\theta \approx 59.036^{\circ}$

$T_{2} = \sqrt{(20\,N)^{2}+(12\,N)^{2}}$

$T_{2} \approx 23.324\,N$

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3 years ago