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Zarrin [17]
3 years ago
12

A car travels from stop A to stop B with a speed of 30 km/h and then returns back to A with a speed of 50 km/h. Find

Physics
1 answer:
andrey2020 [161]3 years ago
6 0
Displacement =20/x
Distance =80/
Average speed =40h
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Diego is playing basketball. While running at 7 km/h toward Gino, he passes the ball to Gino horizontally. The ball travels at 2
enot [183]

TheThe  relative velocity of Deigo will be 27km/h .

<h3>What is relative Velocity? </h3>

The relative velocity is the velocity of an object with respect to another observer. It is the time rate of relative position of one object with respect to another object .

Vab = Va-Vb

Where a is object and b is observer .

We have given here the velocity of ball 20km/ h

and the another velocity is 7km/ h

Let us assume that Diego is also moving in the direction where ball is moving so the relative velocity  will  be

 V = 20+7=27km/ h

When both observer and object is moving in same direction than there sum of velocity will be relative velocity ,if they are moving opposite than subtraction.

to learn more about Relative velocity click Here brainly.com/question/6070547

#SPJ4

3 0
2 years ago
Can you have zero displacement and nonzero average velocity? Zero displacement and nonzero velocity? Illustrate your answers on
Svetlanka [38]

a) Not possible

b) Yes, it's possible (see graph in attachment)

Explanation:

a)

The average velocity of a body is defined as the ratio between the displacement and the time elapsed:

v=\frac{\Delta x}{\Delta t}

where

\Delta x is the displacement

\Delta t is the time elapsed

In this problem, we want to have zero displacement and non-zero average velocity. From the equation above, we see that this is not possible. In fact, if the total displacement is zero,

\Delta x = 0

And therefore as a consequence,

v=0

which means that the average velocity is zero.

B)

Here we want to have zero displacement and non-zero velocity. In this case, it is possible: in fact, we are not talking  about average velocity, but we are talking about (instantaneous) velocity.

On a position-time graph, the instantaneous velocity is the slope of the graph. Look at the graph in attachment. We see that the position of the object first increases towards positive value, then it decreases (the object starts moving backward), then becomes negative, then it increases again until returning to the original position, x = 0.

In all of this, we notice that the total displacement of the object is zero:

\Delta x = 0

However, we notice that the instantaneous velocity of the object at the various instants is not zero, because the slope of the graph is not zero.

Learn more about average velocity:

brainly.com/question/8893949

brainly.com/question/5063905

#LearnwithBrainly

3 0
3 years ago
At a wedding reception, you notice a child who looks like their mass is about 25 kg running across the dance floor then sliding
Vitek1552 [10]

Mass of the object m = 25 kg

Coefficient of friction Uk = 0.15

Frictional force Ff = Uk x F => Ff = Uk x m x g

Ff = 0.15 x 25 x 9.8

Frictional Force Ff = 36.75 N

4 0
3 years ago
Read 2 more answers
Amy swims 500 m (0.5 km) in 6 minutes (0.1 hour ) . What was her speed in kilometers per hour ?
Scorpion4ik [409]
60 minutes = 1h
500/x = 10/100
She swam 5 kilometers per hour.
5 0
3 years ago
A gas at 5.00 atm pressure was stored in a tank during the winter at 5.0 °C. During the summer, the temperature in the storage a
saw5 [17]

Answer:

a) 5.63 atm

Explanation:

We can use combined gas law

<em>The combined gas law</em> combines the three gas laws:

  • Boyle's Law,   (P₁V₁ =P₂V₂)
  • Charles' Law  (V₁/T₁ =V₂/T₂)
  • Gay-Lussac's Law.  (P₁/T₁ =P₂/T₂)

It states that the ratio of the product of pressure and volume and the absolute temperature of a gas is equal to a constant.

P₁V₁/T₁ =P₂V₂/T₂

where P = Pressure, T = Absolute temperature, V = Volume occupied

The volume of the system remains constant,

So, P₁/T₁ =P₂/T₂

a) \frac{5}{278} =\frac{P_2}{313}  \\\\P_2=\frac{5*313}{278}\\ P_2 = 5.63 atm

7 0
3 years ago
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