Answer:
a) R(fw) = 46.75*10⁶ (N)
b) R(rwi) = 70.125*10⁶ [N]
Explanation: See Attached file (the rectangle stands for a jet)
The diagram shows forces acting on the jet
Let R(fw) Reaction of front wheels and
R(rw) Reaction of rear wheels
Now we apply the Stevin relation, for R(fw) and a jet weight as follows
R(fw)/ 4 = 187*10⁶ / 16
Then :
R(fw) = ( 1/4) *187*10⁶ ⇒ R(fw) = 46.75*10⁶ (N)
And e do the same for the reaction on rear wheels
R(rw) / 12 = 187*10⁶ /16 ⇒ R(rw) =(3/4)*187*10⁶
R(rw) = 140,25*10⁶ [N]
The last expression is for the whole reaction, and must be devide by 2
because that force is exerted for two wheels, therefore on each of the two rear wheels the reaction will be:
R(rwi) = 70.125*10⁶ [N]
