Step-by-step explanation:
1) The very first thing to do is read and write down the given data carefully.
From here we can decipher if the intersect asked her is SIMPLE INTEREST or COMPOUND INTEREST.
2) Next step is to put the given values in the appropriate formula correctly and decipher what value is needed to be found.
3) The final step is to do the neat calculations so that there is no error while doing it.
By this we can compute the desired value correctly.
You would add 5 and 17 and that would equal 22
Now it would be 22=J-14
Then add 14 on both sides so it cancels out 22 plus 14 is 36
So J would equal 36
Solution :
Let us consider the squares be ![$[1, 16] \times [16, 32]$](https://tex.z-dn.net/?f=%24%5B1%2C%2016%5D%20%5Ctimes%20%5B16%2C%2032%5D%24)
If x ranges from the 0 to 16 and the y ranges from 16 to 32, we see that the boundary of the region
which goes from the 
.
And so it is easier to find the area of region where 
. This is the triangle with points 
as its vertices.
The area if the triangle is = 
= 
Now the entire area is 
= 256
Then, 
or 
Thus the answer is 
Step-by-step explanation:
6(x+16)-23=37
6x+96-23=37
6x+73=37
6x=-36
x=-6
Surface area of a cuboid
= [2(length)(width)] + [2(width)(height)] + [2(height)(length)]
= {[2(4)(2.5)] + [2(2.5)(2)] + [2(2)(4)]} units²
= (20 + 10 + 16) units²
= 46 units²
