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ololo11 [35]
3 years ago
14

A rectangular conducting loop of wire is approximately half-way into a magnetic field B (out of the page) and is free to move. S

uppose the magnetic field B begins to decrease rapidly in strength
Requried:
What happens to the loop?

1. The loop is pushed to the left, toward the magnetic field.
2. The loop doesn’t move.
3. The loop is pushed downward, towards the bottom of the page.
4. The loop will rotate.
5. The loop is pushed upward, towards the top of the page.
6. The loop is pushed to the right, away from the magnetic field
Physics
1 answer:
Black_prince [1.1K]3 years ago
8 0

Answer:

. The loop is pushed to the right, away from the magnetic field

Explanation

This decrease in magnetic strength causes an opposing force that pushes the loop away from the field

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zhannawk [14.2K]

Answer:

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Explanation:

First we find the fundamental frequency of the rope. The fundamental frequency is the frequency of the rope when it vibrates in only 1 loop. Therefore,

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where,

v = speed of wave = 36 m/s

L = Length of rope = 12 m

f₁ = fundamental frequency

Therefore,

f₁ = (36 m/s)/2(12 m)

f₁ = 1.5 Hz

Now the frequency of nth harmonic is given in general, as:

fn = nf₁

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5 0
3 years ago
a concrete slab 20 m long and weighing 400,000 N is supported by one pillar. A 19,600 N car is parked 8 meters from one end, whe
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from above equation we have

400,000(r - 10) = 19,600 (10 - 8)

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6 0
3 years ago
Read 2 more answers
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