A) When the angle between the Force (F) and Displacement (x) is 0°, because, Work done (W) is directly proportional to the Cosine of the Angle between the Force applied and the resultant displacement of the subject.
W = F•x cos ∅
If ∅ = 0°,
W = F•x ===> Maximum Work Done.
If ∅ = 45°,
W = F•x/√2
If ∅ = 90°,
W = 0
If ∅ = 180°,
W = –F•x ===> Minimum Work Done.
Answer: e. P/2
Explanation:
For ideal gases, we have the relation:
P*V = n*R*T
where:
n = number of mols
R = Gas constant
T = temperature
V = volume
P = pressure.
We know that for sample A, we have n moles, a temperature T and a volume V, then the pressure of this sample will be:
Pa = (n*R*T)/V.
For sample B, we have:
n/2 moles, temperature T/2 and a volume V/2, then the pressure will be:
Pb = (n/2)*R*(T/2)*(2/V) = (n*R*T/V)*(2/4)
and:
(n*R*T/V) = Pa
Then we can replace it and we get:
Pb = (n*R*T/V)*(2/4) = Pa*(2/4) = Pa*(1/2) = Pa/2.
Then the correct option is e.
Answer:
ω = 0.1 rad/s
v = 0.002 m/s
Explanation:
The angular velcoity of the second hand of the clock can be found by:
ω = θ/t
where,
ω = Angular Speed
θ = Angular Displacement
t = time taken
Now, for one complete revolution of second hand of the clock:
θ = 2π rad
t = 60 s
Therefore,
ω = 2π rad/60 s
<u>ω = 0.1 rad/s</u>
Now, for the linear speed (V):
V = rω
where,
V = Linear Speed of Second Hand = ?
r = radius = length of second hand = 0.02 m
Therefore,
V = (0.02 m)(0.1 rad/s)
<u>V = 0.002 m/s</u>
The relationship between frequency and wavelength for an electromagnetic wave is
where
f is the frequency
is the wavelength
is the speed of light.
For the light in our problem, the frequency is
, so its wavelength is (re-arranging the previous formula)
