Question

According to the following reaction, how many grams of hydrofluoric acid will be formed upon the complete reaction of 25.6 grams of water with excess silicon tetrafluoride?
silicon tetrafluoride (s) + water (l) → hydrofluoric acid (aq) + silicon dioxide (s)

Answer 1

Answer:

56.89 g of HF

Explanation:

We'll begin by writing the balance equation for the reaction. This is illustrated below:

SiF₄ + 2H₂O —> 4HF + SiO₂

Next, we shall determine the mass of H₂O that reacted and the mass of HF produced from the balanced equation.

This is illustrated:

Molar mass of H₂O = (2×1) + 16 = 2 + 16 = 18 g/mol

Mass of H₂O from the balanced equation = 2 × 18 = 36 g

Molar mass of HF = 1 + 19 = 20 g/mol

Mass of HF from the balanced equation = 4 × 20 = 80 g

Summary:

From the balanced equation above,

36 g of H₂O reacted to produce 80 g of HF.

Finally, we shall determine the mass of HF produced from the reaction. This is illustrated below:

From the balanced equation above,

36 g of H₂O reacted to produce 80 g of HF.

Therefore, 25.6 g of H₂O will react to produce = (25.6 × 80)/36 = 56.89 g of HF.

Thus, 56.89 g of HF were produced from the reaction.