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Lemur [1.5K]
3 years ago
7

How many valence electrons does a carbon atom have

Chemistry
2 answers:
KATRIN_1 [288]3 years ago
4 0
4.
__________________
Pachacha [2.7K]3 years ago
3 0
It has four electrons
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What is another name for producer why are they called this​
just olya [345]

Answer:

Autotrophs

Explanation:

They are responsible for the production of food. Root words "auto" for self and "troph" for food.

3 0
3 years ago
One example of matter is<br> (1) magnetism<br> (3) water<br> (2) heat<br> (4) radiation
nasty-shy [4]
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5 0
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Why do roads have speed limits rather than velocity limits
Igoryamba
Speed is the rate at which something goes, and velocity is the average acceleration, which means a car can go slow for a bit, and fast for a bit, and have a velocity of medium. Also, speed is much easier to measure. 
6 0
4 years ago
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Sodium sulfate dissolves as follows: Na2SO4(s) → 2Na+(aq) + SO42- (aq). How many moles of Na2SO4 are required to make 1.0 L of s
maxonik [38]

<u>Answer:</u> The number of moles of Na_2SO_4 is 0.05 moles.

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}

We are given:

Molarity of solution = 0.10 mol/L

Volume of solution = 1 L

Putting values in above equation, we get:

0.10mol/L=\frac{\text{Moles of sodium}}{1.0L}\\\\\text{Moles of sodium}=0.10mol

The chemical reaction for the ionization of sodium sulfate follows the equation:

Na_2SO_4(s)\rightarrow 2Na^+(aq.)+SO_4^{2-}(aq.)

By Stoichiometry of the reaction:

2 moles of sodium ions are produced by 1 mole of sodium sulfate

So, 0.10 moles of sodium ions will be produced by = \frac{1}{2}\times 0.1=0.05moles of sodium sulfate.

Hence, the number of moles of Na_2SO_4 is 0.05 moles.

8 0
3 years ago
draw the structure of the isomer that have the molecular formula C5H11Br that is incapable of reacting by E2 mechanism
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Elimination cannot take place if the adjacent Carbon atom has no immediately bonded Hydrogen atom. An isomer of this will by:
(CH₃)₃C-CH₂Br
8 0
4 years ago
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