I would be difficult to remove an electron from a Noble or Inert Gas (also known as the group 8 or 0 elements). This is because they all have filled outermost shells and as such the outermost shell would be held tightly to the nucleus and as such make it difficult to remove. Examples Helium, Neon, Argon, Xenon, Krypton and Radon
Chemical reaction:
2H2S (g) ⇄ 2H2(g) + S2(g)
The equilibrium constant is given by: Kc = [H2]^2 * [S2] / [H2S]^2 = 1.67 * 10^ -7
The initial concentration is 0.0125 mol / 0.500 L = 0.0250 M
Make a table showing the initial concentrations, the change and the final concentrations of each species
2H2S (g) ⇄ 2H2(g) + S2(g)
start 0.0250M 0 0
change - 2x +2x + x
end 0.0250 - 2x 2x x
Kc = (2x)^2 (x) / (0.0250 - 2x)^2
Kc = 4x^3 / (0.0250 - 2x)^2
To solve that equation in an easy way you can assume that 2x is << 0.0250, which leads to
Kc = 4x^3 / (0.0250)^2 = 1.67 * 10^ -7
=> x^3 = 1.67 * 10^ -7 * 0.0250 / 4 = 2.6 * 10 ^-11
=> x = 2.97 * 10^ -4 M
With this you can check that your assumption that x << 0.0250 is good and continue.
From the table you know that the concentrations at equilibrium are:
[H2] = 2x = 2 * 2.97 * 10 ^ -4 M = 5.94 * 10 ^ -4
[S2] = x = 2.97 * 10^ -4 M
Answer:
Neil Armstrong
Explanation:
On July 20, 1969, Neil Armstrong became the first human to step on the moon.
Answer:
Explanation:
Given elements:
Sodium
Fluorine
The ion Na⁺ is made up of 10 electrons, its electronic configuration is:
1s² 2s² 2p⁶
Ion F⁻ is made up of 10 electrons, its electronic configuration is:
1s² 2s² 2p⁶
These ions do not form +2 because they cannot attain stability by losing or gaining two electrons.
Sodium atom is made up of one valence electron. If it loses one electron, it will be isoelectronic with Neon.
Fluorine has 7 valence electrons, to attain stability, it must gain one electron to form an octet. This way it will be isoelectronic with Neon.
Losing or gaining two electrons will not make the elements attain stability.