All categories

3 years ago

Why do some foods test positive for glucose but don't taste sweet?

Chemistry

2 answers:

Mars2501 [29]3 years ago

5 0

Answer:

Some beverages or food that contain no sweet taste or less sweet taste, it does not mean that they have negative test for glucose.

Explanations:

Sweetness is being feel, when it interact with taste bed ( tastes organ on tongue).
Sucrose is consider as a standard sweetener having rating 1.
While is almost sweetener but its rating is 0.7 only that's why some time we don't feel sweetness after using such a food that contain glucose.

Conclusion:

Actually, the metabolic component are breakdown into simpler carbohydrates like sugar, fructose that become source of energy in blood stream. These sugar like glucose are less sweet than sucrose. So we sometimes don't feel sweetness.

podryga [215]3 years ago

4 0

Answer:

The foods that are the carbohydrates, which dissociate into glucose to discharge energy. The foods, which are highest in glucose are starches and are sweet in taste. Some of the foods test positive for glucose, however, do not taste sweet because the over-ingredients overpowers the sweetness taste, and these ingredients are much more stronger than the glucose.

You might be interested in

If the conjugate base of a molecule has a pkb of 1.4, what would you expect the molecule to be?

maw [93]

If the conjugate base of a molecule has a pKb of 1.4, the molecule should be a Weak Acid.

Notice this question gives us the pKb of the molecule, not the pKa. Because of this, the pH scale basically gets reversed, so lower numbers in pKb correlate with stronger bases, and higher numbers in pKb correlate with stronger acids - the exact opposite of the pH scale.

It's important to make sure you completely understand the terms of conjugate base, conjugate acid, pKb, pKa, and how they all relate. It's easy to mix up the meanings of these definitions.

Here are the two other pieces of information you need to know to correctly answer this question:

Strong acids have a weak conjugate base.
Strong bases have a weak conjugate acid.

So if the problem says you have a strong conjugate base, then the molecule must be a weak acid. To illustrate this, think of ammonium, NH4+. Ammonium is a weak acid, but the conjugate base of ammonium is ammonia, NH3, which is a reasonably good base.

Learn more about conjugate base here : brainly.com/question/22514615

#SPJ4

3 0

2 years ago

Heelp

Alchen [17]

Balanced:
1. Na2O + H2O ---> 2NaOH
2. K2O + H2O ---> 2KOH
3. MgO + H2O ---> Mg(OH)2
4. CaO + H2O ---> Ca(OH)2
5. SO2 + H2O ⇄ H2SO3
6. SO3 + H2O ---> H2SO4
All except by 2 were balanced.

7 0

3 years ago

A 2.5 g sample of french fries is placed in a calorimeter with 500.0 g of water at an initial temperature of 21 °C. After combus

SIZIF [17.4K]

Q=m°CΔT
=(500g) x (1 cal/g.°C) x (48°C-21°C) = 13500 cal
13500 cal / 1000 = 13.5 kcal

"What is the caloric value (kcal/g) of the french fries?"
13.5 kcal/ 2.5 g = 5.4 kcal/g

8 0

3 years ago

The atoms of Group B elements _____ electrons when they form ions. options: A.either gain or lose B.gain C.cannot be determined

grigory [225]

The answer to the question :

The atoms of Group B elements _____ electrons when they form ions .

is :

D) lose

The atoms of Group B elements lose electrons when they form ions because these elements are metals.

6 0

3 years ago

Read 2 more answers

Please show all work:

Tom [10]

If 40.0 grams of magnesium is reacted with an excess of nitric acid. 3.3 g of hydrogen gas will be produced.

<h3>What is Stoichiometry ?</h3>

Stoichiometry helps us use the balanced chemical equation to measure quantitative relationships and it is to calculate the amounts of products and reactants that are given in a reaction.

<h3>What is Balanced Chemical Equation ?</h3>

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

Now we have to write the balanced equation

Mg + 2HNO₃ → Mg(NO₃)₂ + H₂

According to Stoichiometry

$40.9\ \text{g Mg} \times \frac{1\ \text{mol Mg}}{24.31\ \text{g Mg}} \times \frac{1\ \text{mol}\ H_2}{1\ \text{mol Mg}} \times \frac{2.02\ g\ H_2}{1\ \text{mol}\ H_2}$

= 3.3 g H₂

Thus from the above conclusion we can say that If 40.0 grams of magnesium is reacted with an excess of nitric acid. 3.3 g of hydrogen gas will be produced.

Learn more about the Stoichiometry here: brainly.com/question/16060223

#SPJ1

8 0

2 years ago