Answer:
Airplane 1- Graph C
Airplane 2- Graph B
Airplane 3- Graph D
Step-by-step explanation:
Answer:
Distance Formula is
Step-by-step explanation:
d=√((x_2-x_1)²+(y_2-y_1)²)
Answer:
≈ 11.78 in
Step-by-step explanation:
The arc length is calculated as
arc = circumference of circle × fraction of circle
= 2πr × 
( cancel 2π on numerator/ denominator )
= 15 × 
= 
≈ 11.78 in ( to 2 dec. places )
Answer:
1.f(x)=2x-5
i will take the set {-2,-1,0,1,2}
f(-2)=2(-2)-5
=-4-5
=-9
f(-1)=2(-1)-5
=-2-5
=-7
f(0)=2(0)-5
=-5
f(1)=2(1)-5
=-3
f(2)=2(2)-5
=-1
so the coordinates of the function is {-9,-7,-5,-3,-1}
2.f(x)=-3x+6
i will the take the set {-2,-1,0,1,2} too
f(-2)=-3(-2)+6=6+6=12
f(-1)=-3(-1)+6=3+6=9
f(0)=-3(0)+6=6
f(1)=-3(1)+6=-3+6=3
f(2)=-3(2)+6=-6+6=0
{12,9,6,3,0}
3.f(x)=2/3.x+4
{-2,-1,0,1,2}
f(-2)=2/3(-2)+4=-4/3+4=(-4+12)/3=8/3
f(-1)=2/3(-1)+4=-2/3+4=(-2+12)/3=10/3
f(0)=2/3(0)+4=4
f(1)=2/3(1)+4=2/3+4=(2+12)/3=14/3
f(2)=2/3(2)+4=4/3+4=(4+12)/3=16/3
{8/3,10/3,4,14/3,16/3}
you're can graph those coordinates
actually you can take other coordinates...
CMIIW
,
Like terms are going to have the EXACT same variables....or they can just be constants with no variables.
x^2 and 3x^2 are like terms
x^2 and x^3 are not like terms
8 and 9 are like terms
8x and 9y are not like terms
so ur like terms in ur problem are : 2y^3 and y^3
