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iogann1982 [59]
3 years ago
10

6^2+17+12 help me plz.

Mathematics
2 answers:
Karo-lina-s [1.5K]3 years ago
7 0
6 squared is 36 because 6x6=36.
Then all you have to do is 36+17+12
which should be: 65
Dmitry_Shevchenko [17]3 years ago
4 0
6^2 + 17 + 12

First, let's start with 6^{2} . Basically, the '2' above the 6 indicates that the number appears twice in multiplying. 6^{2} can be described as 6 × 6 as well. 36 should be your answer for 6 squared.
6^{2} = 6 \times 6 = 36

Second, our problem should look like: 36 + 17 + 12. One can simply do this on a calculator or count on their fingers. Once you add all of the numbers up, you should get 65.

Answer: \fbox {65}
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olga_2 [115]
Supplementary angles add up to 180 degrees.
x + 107 = 180
x + 107 - 107 = 180 - 107
x = 73

The correct answer is B. 73 degrees.

Hope this helps =)
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3 years ago
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3 0
3 years ago
Find the 95% confidence interval for estimating the population mean μ
AVprozaik [17]

We first need to determine whether we are dealing with means or proportions in this problem. Since we are given the sample and population mean, we know that we are dealing with means.

Since we have one sample mean, this means we are creating a confidence interval for one sample (1 Samp T Int).

Normally we would check for conditions, but since this is not formulated as a "real-world scenario" type problem, it is hard to check for randomness and independence. Therefore, I will be excluding conditions from this answer.

<h3>Confidence Interval Formula</h3>

The formula for constructing a <u>confidence interval for means</u> is as follows:

  • \displaystyle \overline{x} \pm t^*\big{(}\frac{\sigma}{\sqrt{n} } \big{)}

We are given these variables:

  • \overline{x}=50
  • n=60
  • \sigma=10

Plug these values into the formula for the confidence interval:

  • \displaystyle 50\pm t^* \big{(}\frac{10}{\sqrt{60} } \big{)}

<h3>Finding the Critical Value (t*)</h3>

In order to find t*, we can use this formula:

  • \displaystyle \frac{1-C}{2}=A

Calculating the z-score associated with "A" will give us t*.

So, let's plug in the confidence interval 95% (.95) into the formula:

  • \displaystyle \frac{1-.95}{2}=.025

Use your calculator or a t-table to find the z-score associated with this area under the curve.. you should get:

  • t^*=1.96

<h3>Constructing Confidence Interval</h3>

Now, let's finish the confidence interval we created:

  • \displaystyle 50\pm 1.96 \big{(}\frac{10}{\sqrt{60} } \big{)}

We can calculate the confidence interval, using this formula, to be:

  • \boxed{(47.4697, \ 52.5303)}

<h3>Interpreting the Confidence Interval</h3>

We are 95% confident that the true population mean μ lies between <u>47.4697 and 52.5303</u>.

8 0
2 years ago
PLS HELP ILL MARK BRAINLIEST
stiv31 [10]

Answer:

210=75x-10x+35

Step-by-step explanation:

So we know to total profit he made is 210 dollars, in which he earned from 3 independent reasons.

The profits he made in per appointment will need a variable because we don't know how many appointments he made. So knowing that we can conclude that 75 dollars and 10 dollars per appointment has to have a variable after it. The same variable as well because both of which are money.

As of the tip, we don't need a variable because it is a one time addtion, he recieved a total of 35 dollars after all of the appointments, so no need to know how many. We already know the total.

So that leaves us to write an equation. The total=$per appointment-fee per appointment+tip. Which becomes 210=75x-10x+35.

Hope this helps!                                          

5 0
3 years ago
What is the slope intercept equation of the line below?
valentina_108 [34]
The answer is letter D
6 0
2 years ago
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