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WITCHER [35]
4 years ago
14

Assume that the box contains 2 defective widgets and18 acceptable widgets. There are 5 inspectors, each of whom selects a widget

from the box at random, inspects it, and then replaces it in the box. Each inspector makes his or her inspection at a different time.
What is the probability that at least one inspector will find a defective
widget?
Mathematics
1 answer:
alina1380 [7]4 years ago
3 0

Probability that any one inspector finds a defective one is

<span>1/9</span> and doesn't find one is <span>8/9</span> so it should be <span>1−(<span>8/9</span><span>)^5</span></span>
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Defining C(n,r) as the number of combinations (order does not count) to choose r objects from n, where C(n,r)=n!/(r!(n-r)!)
there are 
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and
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=30856*741
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