ABC is a equilateral triangle .
Proof :-
Let's assume both circles as C1 and C2 [ as shown in the figure ]
- AB is the radius of circle C1
- AB is the radius of Circle C2
AC is the radius of circle C1.
BC is the radius of circle C2 .
AB and AC both are radius of circle C1 so both are equal ie AB = AC .
AB and BC both are radius of circle C 2 so both are equal ie AB = BC .
Hence we conclude that .
AB = BC = AC.
So the triangle is equilateral triangle.
Answer:
your answer will be option C).0
Step-by-step explanation:
hope it helps you
X - y = -3
y = x + 3.......slope = 1, y intercept = (0,3)
to find x int, sub in 0 for y and solve for x
x - y = -3
x - 0 = -3
x = -3....so the x intercept = (-3,0)
plot ur points (0,3) and (-3,0)......now start at (-3,0)....and since ur slope is 1, go up one, and to the right 1, and up 1, and to the right 1.....do this over as many times as needed and u should cross the y axis at (0,3)
Answer:
A.
Step-by-step explanation:
as u can see,the other acute angle is 43° and the other is also an acute angle and acute angles must not surpass until 80° meaning, the other acute angle is 47°
I- please ask a question. This is not a question
