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4 years ago

What coefficient should be written in front of the reactant Oxygen gas (O2) in order for this equation below to be balanced?

Chemistry

1 answer:

nikitadnepr [17]4 years ago

6 0

Answer:

C₂H₄ + 3O₂ --> 2CO₂ + 2H₂O

Explanation:

In products side we have 4 oxygens from the 2 moles of CO₂ and 2 oxygens from the 2 moles of water. In total, we have 6 O, so as we have 3 atoms of oxygen in reactant side, we must have 3 moles to complete the 6 O.

In reactant side we have 2 C

In product side we have 2 C

In reactant side we have 4 H

In product side we have 4 H ( 2 .2, in water)

In reactant and in product side, we have 6 O

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Imagine you are camping in the desert. Describe two ways you might get water if none was nearby.

VladimirAG [237]

Answer:

An oasis in the middle of the desert or a cactus because they store water inside themselves.

Explanation:

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3 years ago

Read 2 more answers

The molecular ion is not visible in the mass spectrum of 2-chloro-2- methylpropane. At what m/z value would the molecular ion be

pochemuha

Answer: hello the complete question is attached below

Visibility of molecular ion = m/z value of 77

Explanation:

For The molecular ion to be visible, it has to be at an m/z value of 77 and this is because molecular ions will have an m/z ratio = molecular mass of given molecule in most cases but not always in all cases.

And the visibility is possible after the removal of CH₃ ion.

ii) Evidence in the mass spectrum that suggests peak at m/z = 77

attached below

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3 years ago

A substance that will change shape to fit its container but has a definite volume is in a _____ phase of matter

larisa86 [58]

It’s a liquid because it can form any shape to fit container but the amount of liquid always stayed the same unless dropped some.

3 0

4 years ago

Boyle's Law for gases is:

larisa86 [58]

Answer:

b. just a model and therefore accurate for no real gases

Explanation:

Boyle´s Law was determined and is applied for ideal gases, this is, those gases that:

- Do not have any interaction between their particles (neither attraction nor repulsion)

- Any collision between its particles is perfectly elastic

With these conditions, Boyle found that pressure and volume (in a constant temperature) are inversely proportional, which can be expressed as:

PV = k, where “k” is a constant

So, when pressure increases, volume decreases, and viceversa.

If we have to different conditions (1 and 2) of pressure and volume (at constant temperature), this can be expressed like:

P₁V₁ = P₂V₂ = constant

The current and complete equation that links temperature, pressure, mass (in moles) and volume is:

PV = nRT

Real gases do not strictly comply with this law, as its particles has interactions and collisions are not perfectly elastic. This law is more accurate for gases with low molecular mass, and with low pressure and/or high temperature conditions (under these conditions, interactions can be neglected)

Another term that can gives us an idea whether a gas is ideal or not, is the compressibility coefficient Z:

Z = PV/RT

For ideal gases, Z = 1 , as long as the gas moves away from ideality, Z is totally different from 1

3 0

3 years ago

Phenol, c6h5oh, is a stronger acid than methanol, ch3oh, even though both contain an o]h bond. Draw the structures of the anions

timurjin [86]

In resonance structures, the chemical connectivity in the molecule is same but the distribution of electrons are different around the structure. They are created by moving electrons in double or triple bonds, and not atoms.

Phenol, $C_6H_5OH$ and methanol, $CH_3OH$ both are alcohols that contain an $-OH$ group attached to carbon atom.

Due to loss of 1 $H$ from phenol, it forms phenoxide anion and due to presence of double bond in the benzene ring the negative charge on the oxygen atom (which represents electrons) will resonate with double bonds of benzene ring as shown in the image. The resonance-stabilized phenoxide ion is more stable. Whereas when methanol lose 1 $H$ it forms methoxide anion and there are no such electrons present in the structure of methoxide that will result in the movement of electron. Since, due to resonance-stabilized phenoxide ion is more stable than methoxide ion, so it is a stronger acid.

The structures of the anions resulting from loss of 1 $H$ from phenol and methanol is shown in the image.

8 0

3 years ago