Answer:
1) 55.49 g.
2) 383.37 g.
Explanation:
Molarity is the no. of moles of solute in a liter of the solvent.
<em>Molarity (M) = (n of solute)/(Volume of the solution (L))= (mass/molar mass)solute x (1000/V of the solution(ml))</em>
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<em>1) How many grams of solute are in 250 mL of 2.0 M of CaCl₂?</em>
<em>∵ M = (mass/molar mass)CaCl₂ x (1000/V of the solution(ml))</em>
M of CaCl₂ = 2.0 M, V of the solution = 250.0 mL, molar mass of CaCl₂ = 110.98 g/mol.
<em>∴ mass of CaCl₂ = (M)(V of the solution (ml))(molar mass of CaCl₂)/100</em>0 = (2.0 M)(250.0 mL)(110.98 g/mol)/(1000) = <em>55.49 g.</em>
<em>2) How many grams of solute are in 500.0 mL of a 4.4 M solution of K₂SO₄?</em>
<em>∵ M) = (mass/molar mass)</em><em>K₂SO₄</em><em> x (1000/V of the solution(ml))</em>
M of CaCl₂ = 4.4 M, V of the solution = 500.0 mL, molar mass of <em>K₂SO₄</em> = 174.259 g/mol.
<em>∴ mass of K₂SO₄ = (M)(V of the solution (ml))(molar mass of K₂SO₄)/1000</em> = (4.4 M)(500.0 mL)(174.259 g/mol)/(1000) = <em>383.37 g.</em>