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Gnesinka [82]
3 years ago
14

Determinoestablece ensu ushiculosel ciligo de la to NiñezNiñez y de la Adolecencia​

Chemistry
1 answer:
defon3 years ago
4 0
Si nunez y adolécenos reconcile la capitaliza
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Exactly 313.5 J will raise the temperature of 10.0 g of a metal from 25.0 C to 60.0 C. What is the specific heat of the metal?
torisob [31]
From the equation Q = m\cdot c_e\cdot \Delta T we can clear specific heat:

c_e = \frac{Q}{m\cdot \Delta T}\ \to\ c_e = \frac{313.5\ J}{10\ g\cdot (60 - 25)^\circ C} = \bf 0.896\frac{J}{g\cdot ^\circ C}
4 0
3 years ago
How many independent variables can be tested in a standard scientific experiment
Shalnov [3]

One independent variable

6 0
4 years ago
Imagine you are at a local water park on a hot summer day and your feet begin to get hot from the cement. Looking ahead, you not
valkas [14]

Answer:

Sand has less specific heat than water.

Explanation:

Specific Heat is amount of heat needed per unit mass, to raise temperature by 1 degree celsius.

More specific heat means more heat energy needed to increase temperature. It implies - more time needed to absorb heat, increase temperature; and also more time needed to lose its heat.

Less specific heat means less heat energy needed to increase temperature. It implies - less time needed to absorb heat, increase temperature; and also less time needed to lose its heat.

Sand has less specific heat than water. So, it needs less heat absorption to increase temperature by per unit (celsius) ; than water. Hence, same level of heat to both sand & water ; increase temperature of sand more than water, & make it more hot.

8 0
3 years ago
Given that the radius of the helium-4 nucleus is approximately 2.6 fm, the classical electron radius is 2.8 fm, and the calculat
dsp73

Answer:

0.026%

Explanation:

The Helium-4 is the isotope of the helium that has a mass equal to 4. The element has 2 electrons, so, the total radius of the electrons is 2*2.8 = 5.6 fm = 0.0056 pm.

So, the total radius of the particles is 0.0056 + 0.0026 = 0.0082 pm.

The percentage of the space that the particles occupy is the radius of them divided by the radius of the atom:

% = 0.0082/31 *100%

% = 0.026%

* 1 fentometer (fm) = 0.001 picometer (pm)

7 0
3 years ago
What is the nuclear binding energy in joules for an atom of helium–4? Assume the following:
Mice21 [21]

Ang answer at Assume the following: mass defect =5.0531 x 10 - 29 kilograms. Use E =mc2, with c =3 x 108 m/s. At isa pa ang sa got mag aral ng mabuti kyo ah

6 0
4 years ago
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