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Nat2105 [25]
3 years ago
7

After reaching the summit, she descends 14 feet in 213 minutes. If she continues at this rate, where will Maggie be in relation

to the summit after 8 minutes?
Mathematics
1 answer:
Daniel [21]3 years ago
3 0

Complete Question

Maggie is rock climbing. After reaching the summit, she descends 14 feet in 213 minutes. If she continues at this rate, where will Maggie be in relation to the summit after 8 minutes?

Answer:

Maggie will be  x = 0.53 \ feet  from the previous position

Step-by-step explanation:

From the question we are told that

   The distance of descent is  d =  14 ft

    The time  taken is  t =  213 \ minutes

So she descended 14ft  in  213 minutes

 So she would  descend x ft in 8 minutes

   Hence

              x =  \frac{14 * 8 }{213}

             x = 0.53 \ feet

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8 0
3 years ago
Select the situation in which one quantity is changing at a constant rate in relation to another quantity
LenKa [72]
It is called being proportional,

Ex. so every three grapes you eat, i eat four


every 6 you eat, I eat 8, etc. etc.
4 0
3 years ago
What is the value of x in the diagram?
makvit [3.9K]

Answer:

x=5

Step-by-step explanation:

Since this is a right triangle, we can use the pythagorean theorem

a^2 + b^2 = c^2

x^2+ ( 2x+2)^2 = (2x+3)^2

FOIL the squared terms

x^2 +(4x^2 + 4x+4x+4) = 4x^2 + 6x+6x +9

Combine like terms

5x^2+8x +4 = 4x^2 +12x +9

Subtract  4x^2 +12x +9 from each side

5x^2+8x +4  -4x^2 -12x -9= 4x^2 +12x +9-4x^2 -12x -9

x^2 -4x -5 =0

Factor

(x-5) (x+1) = 0

Using the zero product property

x=5   x=-1

But x cannot be negative or we would have negative length

x=5

6 0
3 years ago
Show me how to solve 10>x/2 +4
postnew [5]

Treat this as if the inequality sign was the same thing as an equal sign. Most of the equality rules apply to inequalities (with a few exceptions)

10>\dfrac{x}{2}+4

Subtract both sides by 4

10-4>\dfrac{x}{2}+4-4

6>\dfrac{x}{2}

Multiply both sides by 2

2\times6>\dfrac{x}{2}\times2

12>x

We want the unknown variable on the left side (because it looks nicer)

x

5 0
4 years ago
Read 2 more answers
1. De una encuesta realizada a 120 personas sobre el consumo de albaricoque, banana y coco se obtuvieron el siguiente resultado.
Pachacha [2.7K]

Answer:

El número de personas que consumen dos productos es 30.

Step-by-step explanation:

El primer paso para resolver el problema es realizar los gráficos de los eventos (agregaré como archivo adjunto el gráfico del ejercicio).

En el gráfico podemos ver 7 regiones :

A : Personas que consumen sólo albaricoque.

B : Personas que consumen sólo banana.

C : Personas que consumen sólo coco.

D : Personas que consumen sólo albaricoque y coco.

E : Personas que consumen las tres frutas (albaricoque, banana y coco).

F : Personas que consumen sólo banana y coco.

G : Personas que consumen sólo albaricoque y banana.

Ahora, debemos escribir las ecuaciones que nos brinda el ejercicio :

La encuesta se realizó a 120 personas y se sabe que todas las personas consumen un producto ⇒

A+B+C+D+E+F+G=120 (I)

''El número de personas que consumen sólo albaricoque y coco es la mitad de las que consumen sólo albaricoque''  ⇒

D=\frac{A}{2} (II)

''El número de personas que consumen sólo banana es el doble de las personas que consumen sólo albaricoque y banana más sólo banana y coco'' ⇒

B=2.(G+F) (III)

Finalmente : ''El número de personas que consumen sólo coco más los que consumen los tres productos es 30''  ⇒

C+E=30 (IV)

Finalmente obtenemos el siguiente sistema de ecuaciones :

A+B+C+D+E+F+G=120\\D=\frac{A}{2}\\B=2.(G+F)\\C+E=30

El número de personas que consumen dos productos es :

D+F+G

Entonces, resolvemos escribiendo la primera ecuación conmutando los términos :

A+B+C+E+D+F+G=120 (V)

De (II) se obtiene :

2D=A (VI)

Usamos (VI), (III) y (IV) en (V) ⇒

2D+2(G+F)+30+D+F+G=120  ⇒

2D+2G+2F+30+D+F+G=120

3D+3F+3G=90

Dividiendo esta última ecuación por ''3'' obtenemos :

D+F+G=30

Que es el número de personas que consumen dos productos.

Es muy conveniente seguir el desarrollo del ejercicio mirando el gráfico que adjunto.

8 0
3 years ago
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