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Helen [10]
3 years ago
14

Where are stars from in the spiral galaxy

Chemistry
1 answer:
zzz [600]3 years ago
6 0
Stars form in the regions with the densest gas.
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Colin is writing a story in which a spy damages a fusion nuclear reactor, the reaction runs out of control, and the reactor expl
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The phenomenon that releases uncontrolled amounts of energy very fast is fission, and that is what is used in bombs.
The last option is correct.
4 0
3 years ago
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F(x) = 2|x+2| - 8 I need help ​
Korolek [52]

Answer: |x+2|=xF2+4

Explanation: not sure if this is right im just guessing

8 0
3 years ago
What is a covalent bond?
Aliun [14]
Put simply, a covalent bond is a chemical bond between two atoms where electron pairs are shared. 
8 0
4 years ago
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A 25.0-mL sample containing Cu2+ gave an instrument signal of 25.2 units (corrected for a blank). When exactly 0.500 mL of 0.027
irga5000 [103]

Answer:

The molar concentration of Cu²⁺ in the initial solution is 6.964x10⁻⁴ M.

Explanation:

The first step to solving this problem is calculating the number of moles of Cu(NO₃)₂ added to the solution:

C = \frac{n}{V} \\0.0275 = \frac{n}{0.0005} \\

n = 1.375x10⁻⁵ mol

The second step is relating the number of moles to the signal. We know the the n calculated before is equivalent to a signal increase of 19.9 units (45.1-25.2):

1.375x10⁻⁵ mol _________ 19.9 units

        x              _________  25.2 units

x = 1.741x10⁻⁵mol

Finally, we can calculate the Cu²⁺ concentration :

C = 1.741x10⁻⁵mol / 0.025 L

C = 6.964x10⁻⁴ M

7 0
3 years ago
Perform the following conversions:
jek_recluse [69]

Answer :

The conversion used for the temperature from Fahrenheit to degree Celsius is:

^oC=\frac{5}{9}\times (^oF-32)

The conversion used for the temperature from degree Celsius to Kelvin is:

K=^oC+273

(a) 1.06^oF

^oC=\frac{5}{9}\times (^oF-32)

^oC=\frac{5}{9}\times (1.06^oF-32)

^oC=-17.188

The temperature in degree Celsius is, -17.188^oC

K=^oC+273

K=-17.188+273

K=255.812

The temperature in Kelvin is, 255.812 K

(b) 3410^oC

^oC=\frac{5}{9}\times (^oF-32)

3410^oC=\frac{5}{9}\times (^oF-32)

^oF=6106

The temperature in degree Fahrenheit is, 6106^oF

K=^oC+273

K=3410+273

K=3683

The temperature in Kelvin is, 3683 K

(c) 6.1\times 10^3K

K=^oC+273

6.1\times 10^3K=^oC+273

^oC=5827

The temperature in degree Celsius is, 5827^oC

^oC=\frac{5}{9}\times (^oF-32)

5827^oC=\frac{5}{9}\times (^oF-32)

^oF=10456.6

The temperature in degree Fahrenheit is, 10456.6^oF

8 0
3 years ago
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