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kvv77 [185]
3 years ago
7

Nick wanted to see how high an ice cube would float in different temperatures of water. Identify the independent variable.

Chemistry
2 answers:
xxTIMURxx [149]3 years ago
8 0

Answer:

E. temperature of the water

Explanation:

The independent variable is the variable that changes, and it's also the variable that the dependent variable's results depend on. So depending on the temperature of the water, results in the ice cubes height. So the independent variable is the temperature of the water.

a_sh-v [17]3 years ago
7 0
The answer is E. Temperature of water.
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the latest weather report includes the following statement: the temperature is 78°f, barometric pressure is 29 and the relative
NeX [460]

Answer:

78

Explanation:

6 0
3 years ago
Based on the following thermodynamic data, calculate the boiling point of ethanol in degrees Celsius. Substance ΔH∘f (kJ/mol) S∘
levacccp [35]

Answer:

76.03 °C.

Explanation:

Equation:

C2H5OH(l) --> C2H5OH(g)

ΔHvaporization = ΔH(products) - ΔH (reactants)

= (-235.1 kJ/mol) - (-277.7 kK/mol)

= 42.6 kJ/mol.

ΔSvaporization = ΔS(products) - ΔS(reactants)

= 282.6 J/K.mol - 160.6 J/K.mol

= 122 J/K.mol

= 0.122 kJ/K.mol

Using gibbs free energy equation,

ΔG = ΔH - TΔS

ΔG = 0,

T = ΔH/ΔS

T = 42.6/0.122

= 349.18 K.

Coverting Kelvin to °C,

= 349.18 - 273.15

= 76.03 °C.

8 0
3 years ago
What do you expect will occur as air masses move over cold locations? Hot locations? How does this movement of air masses affect
Maksim231197 [3]

Answer:

Explanation:

When air masses will move over cold location then bottom layer of air cools and become more dense. Due to its high density it is trapped near the ground then it flow towards the equator.

When it moves over hot location then bottom layer gets hot and lighter. Then it moves towards poles.

It changes the temperature and humidity of the climate. making hoter region coll and cooler region a bit hot.

3 0
3 years ago
You wish to add 5 mg/l naocl as cl2 to a solution in a disinfection test, and you have a stock solution (household bleach) that
Alecsey [184]

Answer: -

0.1 ml of bleach should be added to each liter of test solution.

Explanation:-

Let the volume of bleach to be added is B ml.

Density of stock solution = 1.0 g/ml

Mass of stock solution = Volume of stock x density of stock

                                     = B ml x 1.0 g/ml

                                     = B g

Amount of NaOCl in this stock solution = 5% of B g

                                     = \frac{5}{100} x B g

                                     = 0.05 B g

Now each test solution must be added 5 mg/l NaOCl.

Thus each liter of test solution must have 5 mg.

Thus 0.05 B g = 5 mg

                        = 0.005 g

B = \frac{0.005}{0.05}

  = 0.1

Thus 0.1 ml of bleach should be added to each liter of test solution.

4 0
3 years ago
HELP PLEASE I BEG OF YOU
Vitek1552 [10]

Answer:

37.7%

Explanation:

58% of 65 is 37.7%

7 0
2 years ago
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