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Reptile [31]
3 years ago
6

Round 35,124 to the nearest ten thousand

Mathematics
1 answer:
natulia [17]3 years ago
6 0
The answer would be rounded up to 40,000 because of 5 in place value goes. up not down.
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Aaron is 5 years younger then Ron. Four years later, Ron will be twice as old as Aaron. Find their present ages.​
Katyanochek1 [597]

Answer:17

Step-by-step explanation:

tommy  was 14 ten years ago 2times old as ron.14/2=7 . so we add the 10 years ron is 17..c;

6 0
3 years ago
Read 2 more answers
6 out of 24 employees at the water slides are temporary employees what percentage of the employees at the water slide are tempor
kykrilka [37]

Answer:

25%

Step-by-step explanation:

The question is:

6 is what percent of 24?

Set up the problem:

6            x

----   =   -----

24        100

600 / 24  =   25%

Check your answer:

25%   +   25%   +    25%    +  25%      =  100%

 6       +     6      +      6       +     6        =   24

3 0
3 years ago
Determine whether
lora16 [44]

Answer:

(a) and (b) are not equivalent

(c) is equivalent

Step-by-step explanation:

Given

\frac{25^m}{5}

Required

Determine an equivalent or nonequivalent expression

(a)\ 25^{m-1

We have:

25^{m-1

Apply law of indices

25^{m-1} = \frac{25^m}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

(b)\ 25^{2m - 1}

We have:

25^{2m - 1}

Apply law of indices

25^{2m - 1} = \frac{25^{2m}}{25}

<em>This is not equivalent to </em>\frac{25^m}{5}<em></em>

<em></em>

<em />(c)\ 5^{2m-1}<em />

We have:

<em />5^{2m-1}<em />

Apply law of indices

<em />5^{2m-1} = \frac{5^{2m}}{5^1}<em />

<em />5^{2m-1} = \frac{5^{2m}}{5}<em />

<em>Evaluate the numerator</em>

<em />5^{2m-1} = \frac{25m}{5}<em />

<em />

<em>This is an equivalent expression</em>

4 0
2 years ago
Is 2/6 bigger than 3/6
meriva

Answer:

No

Step-by-step explanation:

Since they have the same denominator, you can compare the numerator. Since 2<3, then 2/6 < 3/6.

6 0
3 years ago
Can someone please help with this problem and explain. Please answer quickly, thx :) (picture included)
Anna007 [38]
Exponential laws
(x^{m})^{n}=x^{mn}
x^{\frac{m}{n}}=\sqrt[n]{x^{m}}

so
(m^(2/3))^(1/2)=m^(2/3 times 1/2)=m^(2/6)=m^(1/3)= \sqrt[3]{m^{1}}= \sqrt[3]{m}
3 0
3 years ago
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