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Vsevolod [243]
3 years ago
7

Sasha did an experiment to study the solubility of two substances. She poured 100 mL of water at 20 °C into each of two beakers

labeled A and B. She put 50 g of Substance A in the beaker labeled A and 50 g of Substance B in the beaker labeled B. The solution in both beakers was stirred for 1 minute. The amount of substance left undissolved in the beakers was weighed. The experiment was repeated for different temperatures of water and the observations were recorded as shown.
Part 1: Which substance has a higher solubility?

Part 2: Explain your answer for Part 1.
Chemistry
1 answer:
amm18123 years ago
8 0

Answer:

A

Explanation:

The solubility of a substance is directly proportional to the temperature. It means that solubility will increase with the increases in temperature. At higher temperature, the kinetic energy increased that allow the solvent molecules to break the solute particles more effectively.

Substance A has a higher solubility because the weight of substance A measured at the end of the experiment is less than the weight of substance B.

Hence, the correct answer is A.

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How many grams of LiNO2 are required to make 250 mL of 0.75 Molarity solution?
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Answer:

159 g OF LiNO2 WILL BE USED TO MAKE 0.25 L OF 0.75 M SOLUTION.

Explanation:

How many grams of LiNO2 are required to make 250 mL of 0.75 M?

First calculate the molarity in mol per dm3

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= 3 mol/dm3 of LiNO2

Next is to calculate the molarity in g/dm3:

Molarity in mol/dm3 = molarity in g/dm3 / RMM.

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RMM = ( 7 + 14 + 16 * 2) = 53 g/mol

Molarity in mol/dm3 =  Molarity in g/dm3 / RMM

Molarity in g/dm3 = Molarity in mol/dm3 * RMM

Molarity in g/dm3 = 3 * 53

Molarity in g/dm3 = 159 g/dm3.

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