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Vsevolod [243]
3 years ago
7

Sasha did an experiment to study the solubility of two substances. She poured 100 mL of water at 20 °C into each of two beakers

labeled A and B. She put 50 g of Substance A in the beaker labeled A and 50 g of Substance B in the beaker labeled B. The solution in both beakers was stirred for 1 minute. The amount of substance left undissolved in the beakers was weighed. The experiment was repeated for different temperatures of water and the observations were recorded as shown.
Part 1: Which substance has a higher solubility?

Part 2: Explain your answer for Part 1.
Chemistry
1 answer:
amm18123 years ago
8 0

Answer:

A

Explanation:

The solubility of a substance is directly proportional to the temperature. It means that solubility will increase with the increases in temperature. At higher temperature, the kinetic energy increased that allow the solvent molecules to break the solute particles more effectively.

Substance A has a higher solubility because the weight of substance A measured at the end of the experiment is less than the weight of substance B.

Hence, the correct answer is A.

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Answer:

Q=54.8kJ

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is possible for us to realize that the 46.2 kJ of energy are given per mole of reaction, which are related to 3 moles of hydrogen; Thus, we can calculate the energy per mole of hydrogen as shown below:

\Delta H=\frac{46.2kJ}{mol} *\frac{1mol}{3molH_2}\\\\ \Delta H=15.4\frac{kJ}{molH_2}

Now, to calculate the total energy, we convert the grams to moles of hydrogen as shown below:

Q=7.19gH_2*\frac{1molH_2}{2.02gmolH_2}*15.4\frac{kJ}{molH_2} \\\\Q=54.8kJ

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