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3 years ago

Determine the volume of a piece of gold with a mass of 318.97g

Chemistry

1 answer:

djyliett [7]3 years ago

6 0

Answer:

318 g / 19.32 g v = 16. your volume is 16 hope this helps

Explanation:

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LenKa [72]

Answer:

Explanation: 15

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3 years ago

What is the concentration of the solution prepared by dissolving 2.35 g of KBr (M = 119 g/mol) in 250 mL of water?

dusya [7]

Answer:

The concentration of KBr is $C = 0.07899 \ mol L^{-1}$

Explanation:

From the question we are told that

The mass of KBr is $m_{KBr} = 2.35 \ g$

The molar mass of KBr is $M_{KBr} = 119 g/mol$

Volume of water is $V = 250 \ mL = 250 *10^{-3} = 0.250 \ L$

This implies that the volume of the solution is $V = 250 mL$

The number of moles of KBr is

$n = \frac{m_{KBr}}{M_{KBr}}$

Substituting values

$n = \frac{2.35}{119}$

$n = 0.01975 \ mol$

The concentration of KBr is mathematically represented as

$C = \frac{0.01975}{0.250}$

$C = 0.07899 \ mol L^{-1}$

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3 years ago

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Vladimir [108]

Answer:
Option-A (<span> It would increase from bottom left to top right) is the correct answer.

Explanation:
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