1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
timurjin [86]
3 years ago
13

How much is 20 kilograms in pounds?

Mathematics
2 answers:
Usimov [2.4K]3 years ago
8 0
44.0925 is your answer, try using a unit converter with mass next time.
Natalka [10]3 years ago
3 0
1 kilogram = 2.205 pounds
so
20 * 2.205 = 44.1 pounds
You might be interested in
6 cans of fruit juice cost $2.50. Ned needs to buy 72 cans for a camping trip for the Outdoor Club how much will he spend​
Mrac [35]

Answer:

$30

Step-by-step explanation:

Let 6 cans represent an "order" of fruit juice. 72 cans means 12 orders (72 divided by 6). Since each order costs $2.50, 12 orders costs $30 (12 multiplied by 2.5).

8 0
3 years ago
Read 2 more answers
PLEASE HELPPPP EASY 10 POINTS
wlad13 [49]

Answer:

y=x+5

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find an equation for the line that passes through the points (-6, -6) and (4,-2)
Viefleur [7K]

Answer:

y = 2/5 x - 18/5

Step-by-step explanation:

y = mx + b

m = (y2 - y1)/(x2 - x1) = [-2 - (-6)]/[4 - (-6)] = 4/10 = 2/5

y = 2/5 x + b

-6 = (2/5)(-6) + b

-30 = -12 + 5b

5b = -18

b = -18/5

y = 2/5 x - 18/5

3 0
2 years ago
A pet store has C tanks of fish. Each tank has 38 fish. using C, write an expression for the total number of fish in the store.​
Arisa [49]

Answer:

total number of fish in the store

38 * C fish in store


3 0
3 years ago
What is the probability that a five-card poker hand contains exactly one ace?.
spin [16.1K]

The probability of selecting exactly one ace is its likelihood

The probability that a five-card poker hand contains exactly one ace is 29.95%

<h3>How to determine the probability?</h3>

There are 4 aces in a standard deck of 52 cards.

The probability of selecting an ace would be:

p = 4/52

Also, there are 48 non-ace cards in the standard deck

So, the probability of selecting a non-ace after an ace has been selected is:

p = 48/51

The probability of selecting a non-ace up to the fifth selection are:

  • After two cards have been selected is:  47/50.
  • After three cards have been selected is:  46/49.
  • After four cards have been selected is:  45/48.

The required probability is then calculated as:

P(1 Ace) = n * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)

Where n is the number of cards i.e. 5

So, we have:

P(1 Ace) = 5 * (4/52) * (48/51) * (47/50) * (46/49) * (45/48)

Evaluate

P(1 Ace) = 0.2995

Express as percentage

P(1 Ace) = 29.95%

Hence, the probability that a five-card poker hand contains exactly one ace is 29.95%

Read more about probability at:

brainly.com/question/25870256

8 0
3 years ago
Other questions:
  • Will give brainliest!
    11·1 answer
  • Work out the area of a circle with diameter 1.8cm. Take <img src="https://tex.z-dn.net/?f=%5Cpi" id="TexFormula1" title="\pi" al
    11·1 answer
  • Consider this system of equations. Which equation represents the first equation written in slope-intercept form?
    15·2 answers
  • Write the polynomial in standard form
    15·1 answer
  • Donny joined a club that costs $40 per month. Is the cost over time a proportional or non-proportional relationship?
    15·1 answer
  • Spiral Review Overnight, the temperature decreased by 17 1/2 °F. If the temperature began at -3.6 °F, what is the current temper
    8·1 answer
  • The dimensions of a rectangular prism are shown below: Length: 1 and 1 over 3 feet Width: 1 foot Height: 2 and 1 over 3feet The
    12·2 answers
  • What is the mathematical sum for the equation “1+1” ?
    10·2 answers
  • Hsbhjbhfbghwebfhdfbghef gbhbr ghb erhjtgb
    10·1 answer
  • According to the Centers for Disease Control and Prevention (CDC) , 47% of adults in the United States have hypertension. In a r
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!