All categories

3 years ago

Select all that apply. which of the following are density labels? kg/l g/m g/ml cm^3/g

Chemistry

2 answers:

Strike441 [17]3 years ago

4 0

I would say that only the only density label is cm^3/g

valkas [14]3 years ago

4 0

The density is defined as the ratio of mass of a substance to volume of substance

density = mass / volume

the mass of any substance is measured either in grams or Kilo grams

while volume is measured as : cm^3 or mL or L or m^3

Thus correct answer will be

kg/l

g/ml

You might be interested in

15.1 L N2 at 25 °C and 125 kPa and 44.3 L O2 at 25 °C and 125 kPa were transferred to a tank with a volume of 6.25 L. What is th

Y_Kistochka [10]

Answer:

The total pressure of the mixture in the tank of volume 6.25 litres at 51°C is 1291.85 kPa.

Explanation:

For N2,

Pressure(P₁)=125 kPa

Volume(V₁)=15·1 L

Temperature (T₁)=25°C=25+273 K=298 K

Similarly, for Oxygen,

Pressure(P₂)= 125 kPa

Volume(V₂)= 44.3 L

Temperature(T₂)=25°C= 298 K

Then, for the mixture,

Volumeof the mixture( V)= 6.25 L

Pressure(P)=?

Temperature (T)= 51°C = 51+273 K=324 K

Then, By Combined gas laws,

$\frac{P_{1} V_{1} }{T_{1} } +\frac{P_{2} V_{2} }{T_{2} } =\frac{PV}{T}$

or, $\frac{15.1*125}{298} +\frac{44.3*125}{298} =\frac{P*6.25}{324}$

or, $6.34+18.58=\frac{P*6.25}{324}$

or, $P=\frac{24.92*324}{6.25}$

∴P=1291.85 kPa

So the total pressure of the mixture in the tank of volume 6.25 litres at 51°C is 1291.85 kPa.

3 0

3 years ago

A 50 L cylinder is filled with argon gas to a pressure of 10130.0 kPa at 300°C. How many moles of argon gas does the cylinder co

KengaRu [80]

In this problem, we need to use the ideal gas law. The following is the formula used in ideal gas law: PV = nRT, where n refers to the moles and R is the gas constant.

Given
P = 10130.0 kPa
V = 50 L
T = 300 degree celcius + 273.15 = 573.15 K
R = 8.314 L. kPa/K.mol

Solution
To get the moles which represent the "n" in the formula, we need to rearrange the equation.

PV = nRT PV
---- ------ ---> n = --------
RT RT RT

10130.0 kPa x 50 L
n= ---------------------------------------------
8.314 L. kPa/K.mol x 573.15 K
506,500
= ----------------------------
4,765.17 mol K

=106.29 mol Ar

So the moles of argon gas is 106.29 moles

8 0

3 years ago

Read 2 more answers

4 Na + O2 → 2 Na2O<br><br> 6.79 moles of O2 will react to form how many moles of Na2O?

Nataly_w [17]

Answer:

13.94moles of Na₂O

Explanation:

The balanced reaction expression is given as:

4Na + O₂ → 2Na₂O

Given parameters:

Number of moles of O₂ = 6.97moles

Unknown:

Number of moles of Na₂O

Solution:

To solve this problem;

1 mole of O₂ will produce 2 moles of Na₂O ;

6.97 moles of O₂ will produce 6.97 x 2 = 13.94moles of Na₂O

6 0

2 years ago

Where are atoms located? (check all that apply)*

Jobisdone [24]

I think it’s 2 hope that helped

4 0

3 years ago

Where would you find water on the ph scale?

vladimir2022 [97]

Answer: between 6.5 and 8.5

Explanation:

As shown in my science book it appears in the ph scale

5 0

2 years ago