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3 years ago

What's the major difference between carbon and other group IV elements, excluding allotropy

Chemistry

1 answer:

kogti [31]3 years ago

3 0

Answer:

Carbon has an ability of catenation which other group IV elements lack.

Explanation:

Catenation is the ability for an element to form multiple bonds with other elements leading rise to long chains of compounds.

An example is organic compounds.

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The atomic number of element Y is 119. What should be the atomic number of element X.

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3 years ago

What force on Earth can affect the pull of gravity?

MakcuM [25]

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How many grams of NaOh are produced with the reaction of 5.00 moles of water?

dusya [7]

Answer:

200g

Explanation:

Step 1:

The balanced equation for the reaction.

2Na + 2H2O —> 2NaOH + H2

Step 2:

Determination of the number of mole of NaOH produced by the reaction. This is illustrated below:

From the balanced equation above,

2 moles of H2O produced 2 moles of NaOH.

Therefore, 5 moles of H2O will also produce 5 moles of NaOH.

Step 3:

Conversion of 5 moles of NaOH to grams. This is illustrated below:

Number of mole of NaOH = 5 moles

Molar Mass of NaOH = 23 + 1 + 16 = 40g/mol

Mass of NaOH =?

Mass = number of mole x molar Mass

Mass of NaOH = 5 x 40

Mass of NaOH = 200g

6 0

3 years ago

What is the volume at STP of 3.44 x 1023 molecules of CO2

almond37 [142]

Answer:

C. 12.8 liters.

Explanation:

The Standard Temperature and Pressure (STP) of a gas are 273.15 K and 100 kilopascals. From Avogadro's Law, a mole of carbon dioxide contains $6.022 \times 10^{23}$ molecules. If we suppose that carbon dioxide behaves ideally, then the equation of state for ideal gas is:

$P\cdot V = n\cdot R_{u}\cdot T$ (1)

$P\cdot V = \frac{r\cdot R_{u}\cdot T}{N_{A}}$ (1b)

Where:

$P$ - Pressure, measured in pascals.

$V$ - Volume, measured in liters.

$r$ - Amount of molecules, no unit.

$N_{A}$ - Avogadro's number, no unit.

$R_{u}$ - Ideal gas constant, measured in pascal-liters per mole-Kelvin.

$T$ - Temperature, measured in Kelvin.

If we know that $P = 100000\,Pa$ , $r = 3.44\times 10^{23}$ , $N_{A} = 6.022\times 10^{23}$ , $T = 273.15\,K$ and $R_{u} = 8.314\times 10^{3}\,\frac{L\cdot Pa}{mol\cdot K}$ , then the volume of carbon dioxide at STP is:

$V = \frac{r\cdot R_{u}\cdot T}{N_{A}\cdot P}$

$V = \frac{(3.44\times 10^{23})\cdot \left(8.314\times 10^{3}\,\frac{L\cdot Pa}{mol\cdot K} \right)\cdot (273.15\,K)}{(6.022\times 10^{23})\cdot (100000\,Pa)}$

$V = 12.972\,L$

Therefore, the correct answer is C.

8 0

3 years ago

1. To identify a diatomic gas (X2), a researcher carried out the following experiment: She weighed an empty 4.8-L bulb, then fil

Delvig [45]

Answer:

1) The diometic gas is N2 (molar mass 28 g/mol)

2) The partialpressure of oxygen is 316.6 mmHg

Explanation:

Step 1: Data given

Volume = 4.8 L

pressure = 1.60 atm

temperature = 30.0°C

Difference in mass after weighting again = 8.7 grams

Step 2:

PV = nRT

⇒ with P = the pressure of the gas = 1.60 atm

⇒ with V = the volume of the gas = 4.8 L

⇒ with n = the number of moles = mass/molar mass

⇒ with R = the gas constant = 0.08206 L*atm/k*mol

⇒ with T = the temperature = 30.0 °C = 303 K

(1.60 atm) (4.8L) = (n)*(0.08206)*(303 K)

n = (1.60 * 4.8) / ( 0.08206*303)

n = 0.30888 mol

Step 3: Calculate molar mass

Molar mass = mass / moles

Molar mass = 8.7 grams / 0.3089 moles

Molar mass ≈ 28 g/mol

The diometic gas is N2

2) What is the partial pressure of oxygen in the mixture if the total pressure is 545mmHg ?

Step 1: Calculate mass of nitrogen

Let's assume a 100 gram sample. This means 38.8 grams is nitrogen

Step2: Calculate moles of N2

Moles N2 = mass N2 / molar mass N2

Moles N2 = 38.8 grams / 28 .02 grams

Moles N2 = 1.38 moles

Step 3: Calculate moles of O2

Moles O2 = (100 - 38.8)/ 32 g/mol

Moles O2 = 1.9125 moles O2

Step 4: Calculate molefraction of oxygen

Molefraction O2 = moles of component/total moles in mixture

=1.9125/(1.9125 + 1.38 moles)

=0.581

Step 5: Calculate the partial pressure of oxygen

PO2 =molefraction O2 * Ptotal

=0.581 * 545mmHg

=316.6 mmHg

The partialpressure of oxygen is 316.6 mmHg

7 0

3 years ago

What's the major difference between carbon and other group IV elements, excluding allotropy​

What's the major difference between carbon and other group IV elements, excluding allotropy