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sattari [20]
3 years ago
13

Four equal masses m are located at the corners of a square of side L, connected by essentially massless rods. Find the rotationa

l inertia of this system about an axis
(a) that coincides with one side and
(b) that bisects two opposite sides.
(a) Ia=?
(b) Ib=?
Physics
1 answer:
Marat540 [252]3 years ago
8 0

Answer:

Moment of Inertia: It is the property of an object that measures, how much an object can resist it's rotational motion.

We have 4 masses at the corner of square of length L. The formula of moment of inertia will be

                                             I = mL^{2}

<u>Finding the Rotational Inertia of this system</u>

<em>(a) </em><em>that coincides with one side (Ia):</em>

The moment of inertia of each of the two sides is

                                            I = mL^{2}

so, both sides will have the moment of inertia equals to

                                            I = 2mL^{2}

<em>(b) </em><em>that bisects two opposite sides (Ib):</em>

The distance of all four masses from the axis=  L/2

so, the moment of inertia of all four masses will be

                                             I =4m(L/2)^{2}

                                              I =4m(L^{2})/4

The final value will be

                                             I = mL^{2}

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Thank you for posting your question. I hope that this answer helped you. Let me know if you need more help. 
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