Work is done. work=forcexdisplacement. the ice skater glides 2 meters (displacement), so yes.
Answer:
force for start moving is 7.49 N
force for moving constant velocity 2.25 N
Explanation:
given data
mass = 7.65 kg
kinetic coefficient of friction = 0.030
static coefficient of friction = 0.10
solution
we get here first weight of block of ice that is
weight of block of ice = mass × g
weight of block of ice = 7.65 × 9.8 = 74.97 N
so here Ff = Fa
so for force for start moving is
Fa = weight × static coefficient of friction
Fa = 74.97 × 0.10
Fa = 7.49 N
and
force for moving constant velocity is
Fa = weight × kinetic coefficient of friction
Fa = 74.97 × 0.030
Fa = 2.25 N
The correct answer is B 5,000 rev/s^2
There's no general rule.
Displacement is the length of a straight line from start to finish, and distance is how far you actually traveled from start to finish.
The only thing we really know is that distance can never be shorter than displacement. So I guess the answer is:
<em>The numerical ratio of displacement to distance is always 1 or less</em>.
(But it has to be written ALL IN CAPITALS.)