1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ololo11 [35]
2 years ago
15

You walk into a darkened room and turn on a flashlight. You see an image of the flashlight reflecting off a plane mirror in fron

t of you. The image is 8.4m awat. How far away is the plane mirror? Explain.​
Physics
1 answer:
user100 [1]2 years ago
6 0

Answer:

4.2 is the answer

Explanation

The image formed in a plane mirror is an equal distance behind the mirror as the object in front of it.

Step 1: the equation to this problem would be: 8.4/2

Step 2: 8.4 ÷ 2 = 4.2

You might be interested in
List three things you have done today that used kinetic energy.
Ede4ka [16]
I have thrown a ball during gym.
i have knocked my water bottle off my desk
i have opened a door.
8 0
3 years ago
Read 2 more answers
two projectiles are fired at equal speeds but differentangles. one is fired at an angle of 30 degrees and the other at 60degrees
zheka24 [161]

Answer:

a) 30 degree

Explanation:

As we know that time of flight of the projectile depends on the the vertical component of the velocity always

It is given as

T = \frac{2v_y}{g}

now we know that

v_y = vsin\theta

so we will have

T = \frac{2vsin\theta}{g}

since we know that two projectiles are projected at same speed but different angles

so smaller the angle will take smaller time

so it would be 30 degree projectile which will take smaller time

8 0
3 years ago
The precision of a laboratory instrument is ± 0.05 g. The accepted value for your measurement is 7.92 g. Which measurements are
skelet666 [1.2K]

Answer:

7.89 7.91

Explanation:

The ranges of measurement lie between 7.92-0.05 and 7.92+0.05

7.87g and 7.97g

3 0
3 years ago
Read 2 more answers
When a mass is placed on a spring with a spring constant of 15 newtons per meter, the spring is compressed 0.25 meter. How much
Andre45 [30]

Answer:

0.47 J

Explanation:

The elastic potential energy of a spring is given as,

E = 1/2ke²........................ Equation 1

Where E = Elastic potential energy, k = spring constant, e = extension/compression.

Given: k = 15 N/m, e = 0.25 m.

Substitute into equation 1.

E = 1/2(15)(0.25)²

E = 0.46875

E ≈ 0.47 J.

Hence the elastic potential energy stored in the spring = 0.47 J

7 0
4 years ago
A flea may live on the skin of a dog and feed on the dog's blood. This relationship between the flea and the dog is an example o
AlexFokin [52]
I think it might be a Parasite
8 0
3 years ago
Read 2 more answers
Other questions:
  • Which BEST compares the motions of dots C and D?
    5·2 answers
  • Suppose Earth's gravitational force were decreased by half. How would this change affect a game of basketball? Write a paragraph
    12·2 answers
  • A satellite is orbiting Earth in an approximately circular path. It completes one revolution each day (86,400 seconds). Its orbi
    8·1 answer
  • Special relativity cannot be used to study an object in which frame of reference
    6·2 answers
  • A standard door into a house rotates about a vertical axis through one side, as defined by the door's hinges. A uniform magnetic
    5·1 answer
  • The product of m1m2 in the formula for gravitational force is always
    5·1 answer
  • A small coin of mass m1 is undergoing a uniform circular motion at a velocity v. The radius of the circular path is r. A piece o
    13·1 answer
  • What a brief summary about why taking Athletics is important.
    5·1 answer
  • A cheetah has an acceleration rate of 5.80 m/s2 . What is the cheetah’s final velocity after 7.80 seconds, if initially, his vel
    11·1 answer
  • An object with a mass of 1.5 kg accelerates 10.0 m/s^2? when an unknown force is applied to it. What is the amount of the force?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!