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Answer:
The wavelength of the visible line in the hydrogen spectrum is 434 nm.
Explanation:
It is given that, the wavelength of the visible line in the hydrogen spectrum that corresponds to n₂ = 5 in the Balmer equation.
For Balmer series, the wave number is given by :

R is the Rydberg's constant
For Balmer series, n₁ = 2. So,


or

So, the wavelength of the visible line in the hydrogen spectrum is 434 nm. Hence, this is the required solution.
Answer:
124.86 V
Explanation:
We have to first calculate the voltage drop across the copper wire. The copper wire has a length of 358 ft
1 ft = 0.3048 m
358 ft = 109.12 m
The diameter of 2 AWG copper wire (d) = 6.544 mm = 0.006544 m
The area of the wire = πd²/4 = (π × 6.544²)/4 = 33.6 mm²
Resistivity of wire (ρ) = 0.0171 Ω.mm²/m
The resistance of the wire = 
The voltage drop across wire = current * resistance = 6.1 A * 0.056 ohm = 0.34 V
The voltage at end = 125.2 - 0.34 = 124.86 V
Answer:
103063860 Pa
Explanation:
= Density of seawater = 1030 kg/m³
g = Acceleration due to gravity = 9.81 m/s²
h = Depth at which pressure is being measured = 10.2 km
The gauge pressure is given by

Therefore, the gauge pressure at a depth of 10.2 km is 103063860 Pa
<h2>The option ( c ) is correct </h2>
Explanation:
As the frequency of oscillation of any oscillator is doubled
The velocity of sound v = νλ
here ν is the frequency and λ is the wavelength
Now if ν becomes double , the wavelength λ becomes one half . The velocity of sound remains the same in the same medium .
Thus option ( c ) is correct