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tatyana61 [14]
3 years ago
13

The combustion of gasoline produces carbon dioxide and water. Assume gasoline to be pure octane (C8H18) and calculate the mass (

in kg) of carbon dioxide that is added to the atmosphere per 1.0 kg of octane burned. (Hint: Begin by writing a balanced equation for the combustion reaction.)
Chemistry
1 answer:
Mariulka [41]3 years ago
6 0

Answer:

3.09kg

Explanation:

First, let us write a balanced equation for the reaction. This is illustrated below:

2C8H18 + 25O2 —> 16CO2 + 18H2O

Molar Mass of C8H18 = (12x8) + (18x1) = 96 + 18 = 114g/mol

Mass of C8H18 from the balanced equation = 2 x 114 = 228g

Converting 228g of C8H18 to kg, we obtained:

228/1000 = 0.228kg

Molar Mass of CO2 = 12 + (2x16) = 12 + 32 = 44g/mol

Mass of CO2 from the balanced equation = 16 x 44 = 704g

Converting 704g of CO2 to kg, we obtained:

704/1000 = 0.704kg

From the equation,

0.228kg of C8H18 produced 0.704kg of CO2.

Therefore, 1kg of C8H18 will produce = 0.704/0.228 = 3.09kg of CO2

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The density of aluminium is 2.7 g/cm3. Find the mass in grams of a bar of aluminum measuring 2.7 cm by 1.2 cm by 14.3 cm.
Fofino [41]

Answer:125.0964g

Explanation:

Density = mass/volume

Density = 2.7 gcm-3

Volume=2.7*1.2*14.3=46.332

Mass=?

Mass= density* volume

= 2.7× 46.332=125.0964g

4 0
3 years ago
If a substance has a half life of 58 years and starts with 500 g radioactive, how much remains radioactive after 30 years?
Vilka [71]

Answer:

A = 349 g.

Explanation:

Hello there!

In this case, since the radioactive decay kinetic model is based on the first-order kinetics whose integrated rate law is:

A=Ao*exp(-kt)

We can firstly calculate the rate constant given the half-life as shown below:

k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{58year}=0.012year^{-1}

Therefore, we can next plug in the rate constant, elapsed time and initial mass of the radioactive to obtain:

A=500g*exp(-0.012year^{-1} *30year)\\\\A=349g

Regards!

5 0
3 years ago
if a volume of air occupying 12.0Lat 20celsius is heated to a new temperature of 100 celsius,what would be the new volume
emmasim [6.3K]

Answer:

V₂ = 15.3

Explanation:

Given data:

Initial volume = 12.0 L

Initial temperature = 20°C

Final temperature =100°C

Final volume = ?

Solution:

First of all we will convert the temperature into kelvin.

20°C + 273 = 293 K

100°C + 273 = 373 K

Formula:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 12.0 L × 373 K / 293 k

V₂ = 4476 L.K /293 k

V₂ = 15.3

V₂ = 1566 L.K / 298 K

V₂ = 5.3 L

6 0
3 years ago
One would not expect yeast to undergo fermentation in the presence of
Hunter-Best [27]

Answer:

Oxygen.

Explanation:

Hello,

Yeast fermentation in the food industry must be carried out under anaerobic conditions as long as when oxygen is present respiration occurs rather than fermentation.

Best regards.

3 0
3 years ago
According to the graph, how much Potassium bromide can be dissolved in 100 g of warer at 40C?
xenn [34]
At 40 degrees Celsius, approximately 78 grams of potassium bromide can be dissolved.
6 0
3 years ago
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