Answer:
D. Catalyst
Explanation:
Because a Catalyst is a substance that causes or accelerates a chemical reaction without itself being affected.
Answer:
92.49 %
Explanation:
We first calculate the number of moles n of AgBr in 0.7127 g
n = m/M where M = molar mass of AgBr = 187.77 g/mol and m = mass of AgBr formed = 0.7127 g
n = m/M = 0.7127g/187.77 g/mol = 0.0038 mol
Since 1 mol of Bromide ion Br⁻ forms 1 mol AgBr, number of moles of Br⁻ formed = 0.0038 mol and
From n = m/M
m = nM . Where m = mass of Bromide ion precipitate and M = Molar mass of Bromine = 79.904 g/mol
m = 0.0038 mol × 79.904 g/mol = 0.3036 g
% Br in compound = m₁/m₂ × 100%
m₁ = mass of Br in compound = m = 0.3036 g (Since the same amount of Br in the compound is the same amount in the precipitate.)
m₂ = mass of compound = 0.3283 g
% Br in compound = m₁/m₂ × 100% = 0.3036/0.3283 × 100% = 0.9249 × 100% = 92.49 %
actually the answer is C. 15.0 on ed
Answer:
a. 
b. 
c. 
Explanation:
Hello,
a. By applying the given information, one obtains:

b. By knowing that the propane has a molecular mass of 44g/mol, one obtains:

c. Here, the propane's combustion chemical reaction is stated:

This enthalpy of reaction is computed via:
Δ
Finally, since it is done for 20 lb of propane (
), the obtainable energy is:

Best regards.