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valentina_108 [34]
3 years ago
9

Can any one solve this quiz plz​

Chemistry
1 answer:
yan [13]3 years ago
8 0

Answer:

1. It is stoichiometric.

2. O2 is the limiting reactant.

3. 9.0 g of C2H6 remain unreacted.

4. 17.6 g of CO2.

5. 85.2%.

Explanation:

Hello there!

In this case, for the given chemical reaction:

2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O

We can see that:

1. It is stoichiometric and is balanced because the reactants yields the products according to the law of conservation of mass.

2. In this part, it is possible to calculate the moles of ethane by using its molar mass:

n_{C_2H_6}=15g*\frac{1molC_2H_6}{30.08g} =0.50molC_2H_6

And the moles of oxygen by knowing that one mole is contained in 22.4 L at STP:

n_{O_2}=\frac{1mol}{22.4L} *15.68L=0.7molO_2

Thus, by calculating the moles of carbon dioxide product by each reactant, we can identify the limiting one:

n_{CO_2}^{by\ C_2H_6}=0.50molC_2H_6*\frac{4molCO_2}{2molC_2H_6} =1.0molCO_2\\\\n_{CO_2}^{by\ O_2}=0.70molO_2*\frac{4molCO_2}{7molO_2} =0.4molCO_2\\

Thus, since oxygen yields the fewest moles of CO2 product, we infer it is the limiting reactant.

3. In this part, we calculate the mass of C2H6 that actually react first:

m_{C_2H_6}^{reacted}=0.4molCO_2*\frac{2molC_2H_6}{4molCO_2}*\frac{30.08gC_2H_6}{1molC_2H_6} =6.0gC_2H_6

Thus, the leftover of ethane (C2H6) as the excess reactant is:

m_{C_2H_6 }^{leftover}=15g-6.0g=9.0g6.0C_2H_6

4. Since 0.4 moles of carbon dioxide were produced, we use its molar mass to calculate the mass as its theoretical yield:

m_{O_2}^{theoretical}=0.4molCO_2*\frac{44gCO_2}{1molCO_2}=17.6gCO_2

5. Finally, the percent yield is gotten by dividing the actual yield by the theoretical one:

Y=\frac{15g}{17.6}*100\%\\\\Y=85.2\%

Best regards!

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Benzoic acid, c6h5cooh, has a ka = 6.4 x 10-5. what is the concentration of h3o+ in a 0.5 m solution of benzoic acid? 3.2 x 10-5
FinnZ [79.3K]
The answer for this issue is: 
The chemical equation is: HBz + H2O <- - > H3O+ + Bz- 
Ka = 6.4X10^-5 = [H3O+][Bz-]/[HBz] 
Let x = [H3O+] = [Bz-], and [HBz] = 0.5 - x. 
Accept that x is little contrasted with 0.5 M. At that point, 
Ka = 6.4X10^-5 = x^2/0.5 
x = [H3O+] = 5.6X10^-3 M 
pH = 2.25
(x is without a doubt little contrasted with 0.5, so the presumption above was OK to make) 
3 0
3 years ago
A gas mixture contains oxygen, nitrogen, and carbon dioxide. It has a pressure of 250 mmHg. If the pressure of oxygen is 50 mmHg
kondor19780726 [428]

Answer:

P_{CO_2}=25mmHg

Explanation:

Hello there!

In this case, according to the Dalton's law, which explains that the total pressure of a gaseous system equals the sum of the partial pressures of the gases composing, for the gaseous mixture composed by oxygen, nitrogen and carbon dioxide it would be possible to write:

P_{tot}=P_{N_2}+P_{O_2}+P_{CO_2}

Now, given the pressure of the system and those of oxygen and nitrogen, we calculate that of carbon dioxide as shown below:

P_{CO_2}=P_{tot}-P_{N_2}-P_{O_2}\\\\P_{CO_2}=250mmHg-50mmHg-175mmHg\\\\P_{CO_2}=25mmHg

Best regards!

4 0
2 years ago
How do chemist and physical science relate?
Alex_Xolod [135]
The branch of chemist is a substance of science and pysical is the land science such as a desert of a forest those are chemist and physical science have a good day :)

8 0
3 years ago
If 25.0 g NO are produced, how many grams of nitrogen gas are used?
mr Goodwill [35]

Using the stoichiometry of the reaction and the information provided in the question, the mass of N2 used is 11.62 g.

<h3>Chemical reaction</h3>

The term chemical reaction refers to the combiantion of two or substances to yiled one or more products. The reaction equation in this case is N2 + O2 --->2NO.

Now;

Number of moles of NO = 25g/30 g/mol = 0.83 moles

1 mole of N2 yields 2 moles of NO

x moles of N2 yileds 0.83 moles of NO

x = 0.415 moles

Mass of N2 = 0.415 moles * 28 g/mol = 11.62 g

Learn more about stoichiometry:

brainly.com/question/12166462

8 0
2 years ago
Approximately how many particles are in 3 moles
mash [69]

Answer:

18.066 × 10²³ particles

Explanation:

Given data:

Number of moles = 3 moles

Number of particles = ?

Solution:

The given problem will solve by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

For example,

18 g of water = 1 mole = 6.022 × 10²³ molecules of water

1.008 g of hydrogen = 1 mole = 6.022 × 10²³ atoms of hydrogen

For 3 moles of substance:

One mole = 6.022 × 10²³ particles

3 mol × 6.022 × 10²³ particles/ 1 mol = 18.066 × 10²³ particles

8 0
3 years ago
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