An electrical pole is 12.4m tall. It is supported by a guy wire that is 17.3 long. how far is the anchor of the guy wire to the
1 answer:
The anchor of the guy wire is 12.06 meters away form base of electrical pole.
Further explanation:
The whole given scenario forms a right angle triangle. The pole is standing straight so it is the perpendicular while the guy wire goes from the top of pole to the anchor so it will be the hypotenuse. We have to finds the base.
Pythagoras theorem will be used.
Pythagoras theorem states that:
Given
Base=?
Perpendicular=12.4 m
Hypotenuse = 17.3 m
Putting the values
The anchor of the guy wire is 12.06 meters away form base of electrical pole.
Keywords: Pythagoras theorem, Hypotenuse
Learn more about Pythagoras theorem at:
#LearnwithBrainly
You might be interested in
Answer:
∠A1 = 27.4°, ∠A2 = 56.6°, ∠C1 =104.6°, ∠C2=75.4°, a1 = 79.9 and a2 = 144.9
Step-by-step explanation:
From Sine rule
∴ b / sinB = c / sinC
From the question,
b = 129, c = 168 and ∠B = 48°
∴ 129 / sin48° = 168 / sinC
Then, sinC = (168×sin48)/129
sinC = 0.9678
C = sin⁻¹(0.9678)
C = 75.42
∠C2=75.4°
and
∴∠C1 = 180° - 75.4°
∠C1 =104.6°
For ∠A
∠A1 = 180° - (104.6°+48°) [sum of angles in a triangle]
∠A1 = 27.4°
and
∠A2 = 180° - (75.4° + 48°)
∠A2 = 180° - (123.4°)
∠A2 = 56.6°
For side a
a1/sinA1 = b/sinB
a1/ sin27.4° = 129/sin48
a1 = (129×sin27.4°)/sin48
a1 = 79.8845
a1 = 79.9
and
a2/sinA2 = b / sinB
a2/ sin56.6° = 129/sin48
a2 = (129×sin56.6°)/sin48
a2 = 144.9184
a2 = 144.9
Hence,
∠A1 = 27.4°, ∠A2 = 56.6°, ∠C1 =104.6°, ∠C2=75.4°, a1 = 79.9 and a2 = 144.9