1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
spayn [35]
3 years ago
5

5. Given the cell notation Cu(s)|Cu2+(aq)||Ag+(aq)|Ag(s), what is the half-reaction that occurs at the anode?

Chemistry
2 answers:
KATRIN_1 [288]3 years ago
5 0

Answer:

1) The half-reaction that occurs at the anode is :

Cu(s)\rightarrow Cu^{2+}+2e^-

2)+0.60 V is the E° for the spontaneous reaction.

Explanation:

1)

Oxidation reaction is defined as the reaction in which an atom looses its electrons.

Reduction reaction is defined as the reaction in which an atom gains electrons. Here, the oxidation state of the atom decreases.

Oxidation reaction occurs at anode.

Oxidation half reaction:

Cu(s)\rightarrow Cu^{2+}(aq)+2e^-

Reduction reaction occurs at cathode.

Reduction half reaction:

Ag^{+}(aq)+e^-\rightarrow Ag(s)

Net reaction: Cu(s)+2Ag^{+}(aq)\rightarrow Cu^{2+}(aq)+2Ag(s)

2)

Reduction potential of nickel(II) ions to nickel = E^o_{Ni^{2+}/Ni}=-0.26 V

Reduction potential of copper (II) ions to copper = E^o_{Cu^{2+}/Cu}=0.34 V

To calculate the E^o_{cell} of the reaction, we use the equation:

E^o_{cell}=E^o_{red,cathode}-E^o_{red,anode}

Substance with higher or positive reduction potential goes on cathode and substance with lower of more negative reduction potential goes on anode.

Putting values in above equation, we get:

E^o_{cell}=0.34 V-(-0.26)=0.60 V

+0.60 V is the E° for the spontaneous reaction.

Nataly_w [17]3 years ago
3 0

What is [H+] given that the measured cell potential is -0.464 V and the anode reduction ... What half-reaction occurs at the cathode during the electrolysis of molten ... PbO2(s) + 4H+(aq) + SO42-(aq) + 2e- → PbSO4(s) + 2H2O(l); E° = 1.69 V .... For the cell Cu(s)|Cu2+||Ag+|Ag(s), the standard cell potential is 0.46 V. A cell ... hopw this helps

You might be interested in
90 POINTSSSS!!!
Katarina [22]

Answer:

\large \boxed{\text{-2043.96 kJ/mol}}

Explanation:

Assume the reaction is the combustion of propane.

Word equation: propane plus oxygen produces carbon dioxide and water

Chemical eqn:    C₃H₈(g) +   O₂(g) ⟶   CO₂(g) +   H₂O(g)

Balanced eqn:    C₃H₈(g) + 5O₂(g) ⟶ 3CO₂(g) + 4H₂O(g)

(a) Table of enthalpies of formation of reactants and products

\begin{array}{cc}\textbf{Substance} & \textbf{$\Delta_{\text{f}}$H/(kJ/mol}) \\\text{C$_{3}$H$_{8}$(g)} & -103.85 \\\text{O}_{2}\text{(g)} & 0 \\\text{CO}_{2}\text{(g)} & -393.51 \\\text{H$_{2}$O(g)} & -241.82\\\end{array}

(b)Total enthalpies of reactants and products

\Delta_{\text{rxn}}H^{\circ} = \sum \left( \Delta_{\text{f}} H^{\circ} \text{products}\right) - \sum \left (\Delta_{\text{f}}H^{\circ} \text{reactants} \right)\\= \text{-2147.81 kJ/mol - (-103.85 kJ/mol)}\\=  \text{-2147.81 kJ/mol + 103.85 kJ/mol}\\= \textbf{-2043.96 kJ/mol}\\\text{The enthalpy change is $\large \boxed{\textbf{-2043.96 kJ/mol}}$}

ΔᵣH° is negative, so the reaction is exothermic.

5 0
3 years ago
1<br> 2. How does a detergent remove a stain?<br> ?
Masteriza [31]

Answer:

By using various chemical compounds to lift the stain while being gentle enough to keep fabric intact.

4 0
3 years ago
Menthol, the substance we can smell in mentholated cough drops, is composed of c, h, and o. a 9.045×10−2 −mg sample of menthol i
Ket [755]

Answer:

            Empirical Formula  =  C₁₀H₂₀O

Solution:

Data Given:

                      Mass of Menthol  =  9.045 × 10⁻² mg  =  9.045 × 10⁻⁵ g

                      Mass of CO₂  =  0.2546 mg  =  0.0002546 g

                      Mass of H₂O  =  0.1043 mg  =  0.0001043 g

Step 1: Calculate %age of Elements as;

                      %C  =  (mass of CO₂ ÷ Mass of sample) × (12 ÷ 44) × 100

                      %C  =  (0.0002546 ÷ 9.045 × 10⁻⁵) × (12 ÷ 44) × 100

                      %C  =  (2.814) × (12 ÷ 44) × 100

                      %C  =  2.814 × 0.2727 × 100

                      %C  =  76.73 %


                      %H  =  (mass of H₂O ÷ Mass of sample) × (2.02 ÷ 18.02) × 100

                      %H  =  (0.0001043 ÷ 9.045 × 10⁻⁵) × (2.02 ÷ 18.02) × 100

                      %H  =  (1.153) × (2.02 ÷ 18.02) × 100

                      %H  =  1.153 × 0.1120 × 100

                     %H  =  12.91 %


                      %O  =  100% - (%C + %H)

                      %O  =  100% - (76.73% + 12.91%)

                      %O  =  100% - 89.64%

                     %O  =  10.36 %

Step 2: Calculate Moles of each Element;

                      Moles of C  =  %C ÷ At.Mass of C

                      Moles of C  = 76.73 ÷ 12.01

                     Moles of C  =  6.3888 mol


                      Moles of H  =  %H ÷ At.Mass of H

                      Moles of H  = 12.91 ÷ 1.01

                      Moles of H  =  12.7821 mol


                      Moles of O  =  %O ÷ At.Mass of O

                      Moles of O  = 10.36 ÷ 16.0

                      Moles of O  =  0.6475 mol

Step 3: Find out mole ratio and simplify it;

                C                                        H                                     O

            6.3888                              12.7821                            0.6475

     6.3888/0.6475                  12.7821/0.6475                 0.6475/0.6475

               9.86                                   19.74                                   1

             ≈ 10                                      ≈ 20                                     1

Result:

         Empirical Formula  =  C₁₀H₂₀O₁

8 0
3 years ago
Chloroform is an excellent solvent for extracting caffeine from water. The distribution coefficient, KD, (Cchloroform/Cwater) fo
Art [367]

The relative volumes of chloroform and water that should be used is 9:10

Concentration of solution in chloroform = 90 ( moles of chloroform )

Concentration of solution in water = 10 ( moles of water )

Dissociation constant at 25^oC; K_D = 10

K_D = Concentration of solution in chloroform / Concentration of solution in water

Meaning;

K_D = \frac{\frac{mole\ of\ chloroform}{volume\ of\ chloroform} }{\frac{mole\ of\ water}{volume\ of\ water} }

Since 90 mole is present in chloroform and 10 mole is present in water, Total mole of Caffeine present is 100

Now, we substitute our given values into the equation

10 = \frac{\frac{90}{volume\ of\ chloroform} }{\frac{10}{volume\ of\ water} }\\\\10 *\frac{10}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform}  \\\\\frac{100}{volume\ of\ water} = \frac{90}{volume\ of\ chloroform}\\\\\frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{90}{100}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = \frac{9}{10}\\\\ \frac{volume\ of\ chloroform}{volume\ of\ water} = 9:10

Therefore, the relative volumes of chloroform and water that should be used is 9:10

Learn more; brainly.com/question/11060225

8 0
3 years ago
Công thức toingr quát anken
Maksim231197 [3]

Answer:

ndcjc  kin ksklp

Explanation:

4 0
3 years ago
Other questions:
  • How can valence electrons be used to predict the type of compounds formed?
    13·1 answer
  • A majority of the 118 elements on the periodic table are classified as
    11·1 answer
  • what volume (L) of fluorine gas is required to react with 2.31 g of calcium bromide to form calcium fluoride and bromine gas at
    14·1 answer
  • Can someone help me with this question??
    13·1 answer
  • What is the active component of dynamite
    5·1 answer
  • What is the concentration,in molarity, of a solution containing 10 moles of copper(ii) nitrate in 5.0 liters of solution?
    6·1 answer
  • Question 1 (1 point)
    7·2 answers
  • A Write a set of four quantum numbers possible for the circled electron in arsenic (As). (There could be more
    6·1 answer
  • How many moles of N 2 make 1.76 moles of NH 3 ? do you need to. Please help me!
    5·1 answer
  • A flask contains two gases: the first gas has a pressure of 0.75 atm and the second gas has a
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!