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Westkost [7]
3 years ago
10

Can someone please explain to me how to find the molar mass of hydrated sodium thiosulfate. I put the formula in above if you ne

ed it.​

Chemistry
2 answers:
MakcuM [25]3 years ago
8 0

Answer:

Is that all in the Image take a bigger pic

Explanation:

Veronika [31]3 years ago
7 0

Answer:

Name: Sodium Thiosulfate Pentahydrate.

Formula: Na2S2O3.5H2O.

Molar Mass: 248.1841.

Explanation:

Hope this helps :D

and feel free to click that thanks button

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How many liters would 4.56 mol sulfur dioxide occupy at STP?
algol13

The volume of Sulfur dioxide-SO₂ at STP : = 102.144 L

<h3>Further explanation</h3>

Given

4.56 mol Sulfur dioxide-SO₂

Required

The volume

Solution

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters/mol.

so for 4.56 mol :

= 4.56 x 22.4 L

= 102.144 L

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What sequence should be followed when conducting a laboratory investigation? Make observations, gather experimental data, form a
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Define a problem, form a hypothesis, gather experimental data, form a conclusion

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Write three primary alcohol with the formula C4H8O​
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What is the volume of an alka seltzer tablet
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Answer:

Explanation:

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A solution made by dissolving 33 mg of insulin in 6.5 mL of water has an osmotic pressure of 15.5 mmHg at 25°C. Calculate the mo
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<u>Answer:</u> The molar mass of the insulin is 6087.2 g/mol

<u>Explanation:</u>

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

Or,

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = 15.5 mmHg

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (insulin) = 33 mg = 0.033 g   (Conversion factor: 1 g = 1000 mg)

Volume of solution = 6.5 mL

R = Gas constant = 62.364\text{ L.mmHg }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

15.5mmHg=1\times \frac{0.033\times 1000}{\text{Molar mass of insulin}\times 6.5}\times 62.364\text{ L.mmHg }mol^{-1}K^{-1}\times 298K\\\\\text{molar mass of insulin}=\frac{1\times 0.033\times 1000\times 62.364\times 298}{15.5\times 6.5}=6087.2g/mol

Hence, the molar mass of the insulin is 6087.2 g/mol

8 0
3 years ago
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