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3 years ago

. Explain how surface waves can have characteristics of both longitudinal waves and transverse waves.

Physics

1 answer:

Annette [7]3 years ago

5 0

Answer:

This whole concept depends on the depends on the direction of propagation of the surface wave or displacement of wave such that if its in direction of wave velocity its said to features of longitudinal wave and if its in direction at 90° to wave velocity its said to have transverse features

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Which table is it I’ll mark brainlest

alexira [117]

Answer:

we need the graph to answer the question.

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3 years ago

If the temperature rises by 9. 9 degrees, what is the corresponding temperature increase in degrees celsius?

Yanka [14]

Main Answer:

Assume that the temperature rises by 9.9 F

Initial Temperatures will be C1, F1

Final temperatures will be C2, F1 + 9.9

The relation between celsius and fahrenheit temperature is as follows:

C = 5/9(F - 32)

Increase in temperature in celsius will be

C2 - C1 = F2 - F1

C2 - C1 = 5/9 ( F1 +9.9 -32) - 5/9 ( F1 -32)

C2 - C1 = 5/9 ( F1 +9.9 -32 - F1 +32)

C2 - C1 = 5/9 (9.9)

C2 - C1 = 5.5C

Explanation:

What is temperature?

Temperature is defined as the degree of coldness or hotness of an object or a substance. Generally, it is measured in various temperature scales. They are celsius, fahrenheit, kelvin.

To know more about temperature, please visit:

brainly.com/question/25677592

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7 0

2 years ago

What happens to an object at rest if balanced forces act upon it?

Ilya [14]

Explanation:

it will collide then friction will slow it down

4 0

3 years ago

A fuse in an electric circuit is a wire that is designed to melt, and thereby open the circuit, if the current exceeds a predete

arlik [135]

Answer:

0.0389 cm

Explanation:

The current density in a conductive wire is given by

$J=\frac{I}{A}$

where

I is the current

A is the cross-sectional area of the wire

In this problem, we know that:

- The fuse melts when the current density reaches a value of

$J=520 A/cm^2$

- The maximum limit of the current in the wire must be

I = 0.62 A

Therefore, we can find the cross-sectional area that the wire should have:

$A=\frac{I}{J}=\frac{0.62}{520}=1.19\cdot 10^{-3} cm^2$

We know that the cross-sectional area can be written as

$A=\pi \frac{d^2}{4}$

where d is the diameter of the wire.

Re-arranging the equation, we find the diameter of the wire:

$d=\sqrt{\frac{4A}{\pi}}=\sqrt{\frac{4(1.19\cdot 10^{-3})}{\pi}}=0.0389 cm$

3 0

3 years ago

A plane travels down a runway 2750 m before it lifts off at an angle of 37 degrees from the horizontal. The plane has traveled 1

ss7ja [257]

Answer: 4.236km

Explanation:

Let's define the point (x, y) as:

x = horizontal distance moved.

y = vertical distance moved.

If the plane starts in the point (0, 0) then:

"A plane travels down a runway 2750 m before it lifts off..."

At this time, the position will be:

P = (0 + 2750m, 0) = (2750m, 0).

"it lifts off at an angle of 37 degrees from the horizontal. The plane has traveled 1.8 km since its wheels left the ground."

In this case, as the angle is measured from the horizontal, the components will be:

x = 1.8km*cos(37°) = 1.438km

y = 1.8km*sin(37°) = 1.083 km

Then the new position is:

P = (2750m + 1.438 km, 0 + 1.083 km)

Let's write it using the same units for all the quantities:

we know that

1km = 1000m

Then:

2750m = (2750/1000) km = 2.750 km.

Then we can write the new position as:

P = (2.750 km + 1.438km, 1.083km) = (4.188km, 1.083km)

Now, we define the displacement as the distance between the final position and the initial position.

The distance between two points (a, b) and (c, d) is:

D = √( (a c)^2 + (b - d)^2)

In this case the points are:

(0, 0) for the initial position

(4.188km, 1.083km) for the final position.

And the displacement will be:

D = √( (4.188km - 0)^2 + (1.083 - 0)^2) = 4.236km

5 0

3 years ago