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Ulleksa [173]
3 years ago
13

Explain why glucose is important to a cell

Physics
1 answer:
ELEN [110]3 years ago
5 0
Glucose is important to plants because it is a source of energy that can be converted into other components like starch or cellulose; these components are necessary forcell structures such as the cell walls and for the plant's development.Glucose is also necessary for respiration in plants.
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Answer: A

Explanation:

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2 years ago
If 0.5 A is flowing through a household light
stiks02 [169]

Answer:

60W

Explanation:

P=IV=0.5x120

P =60W

5 0
3 years ago
A 2300-kg car slows down at a rate of 3.0 m/s2 when approaching a stop sign. What is the magnitude of the net force causing it t
weeeeeb [17]

The magnitude of the net force causing the 2300kg car to slow down is 6900N

HOW TO CALCULATE FORCE:

  • The net force applied on a moving object can be calculated by multiplying the mass of the object by its acceleration. That is;

  • Force (N) = mass (kg) × acceleration (m/s²)

  • According to this question, a 2300-kg car slows down at a rate of 3.0 m/s2 when approaching a stop sign. The net force causing the car to stop can be calculated as follows:

F = 2300kg × 3m/s²

F = 6900N

  • Therefore, the magnitude of the net force causing the 2300kg car to slow down is 6900N.

Learn more at: brainly.com/question/18109210?referrer=searchResults

4 0
3 years ago
Astronomers have found water on mars.
vodomira [7]

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4 0
2 years ago
If a car takes a banked curve at less than a given speed, friction is needed to keep it from sliding toward the inside of the cu
zubka84 [21]

Answer:

minimum speed is 15.35 m/s

frictional coefficient  is 0.26

Explanation:

given data

radius = 84 m

angle = 16°

speed = 16 km/h = 4.43 m/s

to find out

minimum speed and   minimum coefficient

solution

we will apply here formula for velocity that is

velocity² = radius × g × tanθ

v² = 84 × 9.8 × tan16

v² =  236.04

v = 15.35 m/s

and

we find first friction force here

friction force 1 = m v² /r

friction force 1 = m (15.35)² / 84 = 2.80 m

and

friction force 2 = m v² /r

friction force 2 = m (4.43)² / 84 =  0.245 m

so total friction force = f1 - f2

total friction force = 2.80 - 0.245  = 2.55 m

so frictional coefficient = friction force /g

frictional coefficient = 2.55 / 9.8

so frictional coefficient  is 0.26

4 0
3 years ago
Read 2 more answers
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