A) f = 1.8 rev/s = 2 Hz
<span>T = 1 / f = 0.55s
B) not really sure..srry
C) </span><span>T = 2 pi √ ( L / g ) </span>
<span>0.57 = 2 x 3.14 x √ ( 0.2 / g )
</span><span>
g = 25.5 m/s²
</span>
Hope this helps a little at least.. :)
We can use constant acceleration equation to solve for the distance.
Formula is:
Vf^2 = Vi^2 + 2ad
where Vf^2 is final velocity squared, Vi^2 is initial velocity squared, a is acceleration (or deceleration) and d is the distance.
we want the car to come to complete stop, that is, Vf^2 be equal to zero.
Therefore, the equation becomes 0 = Vi^2 + 2ad. Solving for d we get:
d = (-(Vi)^2)/2a). We can ignore the minus sign since acceleration is really deceleration.
We know initial velocity (23m/s) and we know acceleration (max= 300 m/s^2). Plugging these in, we get:
d = ((23 m/s)^2)/(2* 300m/s^2) = <span>0.88m </span>
<span>hope that helps</span>
Answer:60 gm
Explanation:
Given
initial velocity of ball 
Force exerted by racquet 
time period of force 
final velocity of ball 
Racquet imparts an impulse to the ball which is given by
Answer:
A
Explanation:
velocity is measured in m/s
acceleration has units m/s^2
so divide the velocity change by the time change:
20 m/s / 80 s = 20 / 80 = .25 m/s^2
Quoting from the article itself:
"Since it is above Earth's atmosphere, it gives us clearer pictures of space than telescopes on Earth can."
