Question

Plz help me!!!! A spring is connected to a wall as shown below. A mass on a horizontal surface is connected to the springs and pulled to the right along the surface stretching the spri bf by 25cm.

Answer 1

Answer:

320 N/m

Explanation:

F = k·Δx

where

F is the restoring force of the spring

k is the proportionality constant called the ‘spring constant’

Δx is the change in the spring’s position due to the deformation.

You need the k so

25 cm= 0.25m

k=F/∆x = 80/0.25 = 320 N/m