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Pavel [41]
3 years ago
14

Why does Mila’s phone start playing music again when she plugged her phone into the battery pack ?

Physics
1 answer:
denis-greek [22]3 years ago
3 0

Answer:

cause it got charged

Explanation:

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How much work is done when a 4.0-newton box is carried horizontally a distance of 2.0 meters at a constant velocity?
monitta

Answer: Work done by the box will be 8 Joules.

Explanation:

Work done by a substance is the product of the force applied on it and the displacement of a substance.

Mathematically,

W=F.s

Where,

W = work done = ? J

F = Force applied = 4 N

s = displacement = 2 m

Putting values in above equation, we get:

W=4N\times 2m=8Nm=8J

Hence, work done by the box will be 8 Joules.

4 0
3 years ago
Read 2 more answers
A lunar exploration vehicle was created by a research team. It weighs 3,000 kg on the earth. It needs an acceleration of 10 m/s2
Arada [10]
Answer = 30,000 N

EXPLANATION

Applying Newton’s second of law of motion, which in summary, states that t<span>he acceleration of an object... is directly proportional to the magnitude of the net force... and inversely proportional to the mass of the object.
</span><span>
Therefore, Force = Mass * Acceleration
F = ma

Mass, m = </span><span>3,000 kg
</span>Acceleration, a = <span>10 m/s</span>²<span>
</span>Force, F = 3,000 × 10
= 30,000 N
6 0
3 years ago
A sprinter accelerates at 7.5 m/s from rest in 2.0 s, what distance did she go? (15 m)
a_sh-v [17]

Answer:

<em>The sprinter traveled a distance of 7.5 m</em>

Explanation:

<u>Motion With Constant Acceleration </u>

It's a type of motion in which the rate of change of the velocity of an object is constant.

The equation that rules the change of velocities is:

v_f=v_o+at\qquad\qquad [1]

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

The distance traveled by the object is given by:

\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]

Using the equation [1] we can solve for a:

\displaystyle a=\frac{v_f-v_o}{t}

The sprinter travels from rest (vo=0) to vf=7.5 m/s in t=2 s. Computing the acceleration:

\displaystyle a=\frac{7.5-0}{2}

a=3.75\ m/s^2

Now calculate the distance:

\displaystyle x=0*2+\frac{3.75*2^2}{2}

\displaystyle x=7.5\ m

The sprinter traveled a distance of 7.5 m

8 0
3 years ago
Wave interactions
rewona [7]

Hi! I want to know this

6 0
3 years ago
A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest fro
Oksi-84 [34.3K]

Answer:

the equation of motion is

x(t) =-\frac{1}{6} \cos4\sqrt{6} t

Explanation:

Given that,

The weight attached to the spring is 24pounds

Acceleration due to gravity is 32ft/s²

Assume x is the string length, 4inches

convert the length inches to to feet = 4/12 = 1/3feet

From Hookes law , we calculate the spring constant k

k = W / x

k = 24 / (1/3)

k = 24 / 0.33

k = 72lb/ft

If the mass is displace from its equilibrium position by amount x

the differential equation is

m\frac{d^2x}{dt^2} + kx=0\\\\\frac{3}{4 } \frac{d^2x}{dt^2}+72x=0\\

\frac{d^2x}{dt^2} +96x=0

Auxiliary equation is

m^2+96=0\\m=\sqrt{-96} \\m=\_ ^+4\sqrt{6}

Thus the solution is,

x(t) =  c_1cos4\sqrt{6t} +c_2sin\sqrt{6t}

x'(t) =-4\sqrt{6c_1} sin4\sqrt{6t} +c_24\sqrt{6} cos4\sqrt{6t}

The mass is release from rest

x'(0) = 0

-4\sqrt{6c_1 }  \sin4\sqrt{6} (0)+c_24\sqrt{6} \cos4\sqrt{6} (0)=0\\c_24\sqrt{6} =0\\\\c_2=0

Therefore

x(t) = c₁ cos4 √6t

x(0) = -2inches

c₁ cos4 √6(0) = 2/12feet

c₁= 1/6feet

There fore, the equation of motion is

x(t) =-\frac{1}{6} \cos4\sqrt{6} t

7 0
4 years ago
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