Answer: Work done by the box will be 8 Joules.
Explanation:
Work done by a substance is the product of the force applied on it and the displacement of a substance.
Mathematically,

Where,
W = work done = ? J
F = Force applied = 4 N
s = displacement = 2 m
Putting values in above equation, we get:

Hence, work done by the box will be 8 Joules.
Answer = 30,000 N
EXPLANATION
Applying Newton’s second of law of motion, which in summary, states that t<span>he acceleration of an object... is directly proportional to the magnitude of the net force... and inversely proportional to the mass of the object.
</span><span>
Therefore, Force = Mass * Acceleration
F = ma
Mass, m = </span><span>3,000 kg
</span>Acceleration, a = <span>10 m/s</span>²<span>
</span>Force, F = 3,000 × 10
= 30,000 N
Answer:
<em>The sprinter traveled a distance of 7.5 m</em>
Explanation:
<u>Motion With Constant Acceleration
</u>
It's a type of motion in which the rate of change of the velocity of an object is constant.
The equation that rules the change of velocities is:
![v_f=v_o+at\qquad\qquad [1]](https://tex.z-dn.net/?f=v_f%3Dv_o%2Bat%5Cqquad%5Cqquad%20%5B1%5D)
Where:
a = acceleration
vo = initial speed
vf = final speed
t = time
The distance traveled by the object is given by:
![\displaystyle x=v_o.t+\frac{a.t^2}{2}\qquad\qquad [2]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%3Dv_o.t%2B%5Cfrac%7Ba.t%5E2%7D%7B2%7D%5Cqquad%5Cqquad%20%5B2%5D)
Using the equation [1] we can solve for a:

The sprinter travels from rest (vo=0) to vf=7.5 m/s in t=2 s. Computing the acceleration:


Now calculate the distance:


The sprinter traveled a distance of 7.5 m
Answer:
the equation of motion is

Explanation:
Given that,
The weight attached to the spring is 24pounds
Acceleration due to gravity is 32ft/s²
Assume x is the string length, 4inches
convert the length inches to to feet = 4/12 = 1/3feet
From Hookes law , we calculate the spring constant k
k = W / x
k = 24 / (1/3)
k = 24 / 0.33
k = 72lb/ft
If the mass is displace from its equilibrium position by amount x
the differential equation is


Auxiliary equation is

Thus the solution is,


The mass is release from rest
x'(0) = 0

Therefore
x(t) = c₁ cos4 √6t
x(0) = -2inches
c₁ cos4 √6(0) = 2/12feet
c₁= 1/6feet
There fore, the equation of motion is
