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Norma-Jean [14]
3 years ago
7

Explain how to use a graph to show whether or not the speed of an object is constant.

Chemistry
1 answer:
Sonbull [250]3 years ago
3 0

Answer:

A horizontal line on a speed-time graph represents a constant speed. A sloping line on a speed-time graph represents an acceleration. The sloping line shows that the speed of the object is changing. The object is either speeding up or slowing down.

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Round each number to four significant figures
ira [324]

Answer:

a.

84,791 » 8479

b.

256.75 » 256.8

c.

431,801 » 4318

d.

0.00078100 » 0.0007810

Explanation:

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5 0
2 years ago
What is an intensive property? *
Dennis_Churaev [7]

Answer:A property that changes if the amount of substance changes

Explanation:

This is the answer

8 0
3 years ago
Which of the following is not present in skeletal structures?
cupoosta [38]

Answer:

cartilage or soft tissue? you didn't give options :/

Explanation:

6 0
3 years ago
when 32.4 g of water vapor condenses, how much heat is given off? The heat of vaporization for water is 40.67 kj/mol
egoroff_w [7]
When a water vapor condenses, heat is being released from the process. This heat is called latent heat of vaporization since the phase change happens without any change in the temperature. This value is constant per mole of a substance as a function of pressure and temperature. For this problem, we are given the heat of vaporization at a certain T and P. We use this value to calculate the total heat released from the process. We calculate as follows:

Total heat released: 32.4 g ( 1 mol / 18.02 g ) (40.67 kJ / mol) = 73.12 kJ

Therefore, 73.12 kJ of heat is released from the condensation of 32.4 g of water vapor.
3 0
3 years ago
What is the final concentration of a solution prepared by diluting 35.0 ml of 12.0 m hcl to a final volume of 1.20 l? what is th
Dafna1 [17]
We know that, M1V1     =     M2V2
                        (Initial)          (Final)
where, M1 and M2 are initial and final concentration of soution respectively. 
V1 and V2 = initial and final volume of solution respectively

Given: M1 = 12 m, V1 = 35 ml and V2 = 1.2 l = 1200 ml

∴ M2 = M1V1/V2 = (12 × 35)/ 1200 = 0.35 m
Final concentration of solution is 0.35 m
8 0
3 years ago
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