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Fudgin [204]
3 years ago
5

If 2a=3b and a=6 then b=

Chemistry
2 answers:
Ne4ueva [31]3 years ago
6 0

then b is 4

2a=3b since a=6

2x6=3b

12=3b

b=12/3

b=4

Naya [18.7K]3 years ago
4 0

Answer:

b=4

Explanation:

2a=3b

2a=2*6

2*6=12

2a=12

12=3b

12/3=4

b=4

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Calculate the number of moles of NaOH contained in 250. mL of a 0.05M solution.
steposvetlana [31]

Answer:

0.0125mol

Explanation:

Molarity (M) = number of moles (n) ÷ volume (V)

n = Molarity × Volume

According to this question, a 0.05M solution contains 250 mL of NaOH. The volume in litres is as follows:

1000mL = 1L

250mL = 250/1000

= 0.250L

n = 0.05 × 0.250

n = 0.0125

The number of moles of NaOH is 0.0125mol.

3 0
3 years ago
Who can help me with this? Asap
aivan3 [116]

Answer:

A. = 143

B. = 8

C. =32

Explanation:

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3 0
3 years ago
1.674×10-4 mol of an unidentified gaseous substance effuses through a tiny hole in 86.6 s. Under identical conditions, 1.715×10-
siniylev [52]
<h2>Answer:</h2>

44.06 g/mol

<h3>Explanation:</h3>

We are given;

  • Number of moles of unidentified gas as 1.674×10^-4 mol
  • Time of effusion of unidentified gas 86.6 s
  • Number of moles of Argon gas as 1.715×10^-4 mol
  • Time of effusion of Argon gas is 84.5 s

We are supposed to calculate the molar mass of unidentified gas

<h3>Step 1: Calculate the effusion rates of each gas</h3>

Effusion rate = Number of moles/time

Effusion rate of unidentified gas (R₁)

 =  1.674×10^-4 mol ÷ 86.6 s

 = 1.933 × 10^-6 mol/s

Effusion rate of Argon gas (R₂)

 = 1.715×10^-4 mol ÷ 84.5 sec

= 2.030 × 10^-6 mol/s

<h3>Step 2: Calculate the molar mass of unidentified gas</h3>
  • Assuming the molar mass of unidentified gas is x;
  • We can use the Graham's law of effusion to find x;
  • According to Graham's law of diffusion;

\frac{R_{1}}{R_{2}}}=\frac{\sqrt{MM_{Ar}}}{\sqrt{X}}

But, Molar mass of Argon is 39.948 g/mol

Therefore;

\frac{1.933*10^-6mol/s}{2.030*10^-6mol/s}}=\frac{\sqrt{39.948}}{\sqrt{X}}

0.9522=\frac{\sqrt{39.948}}{\sqrt{X}}

Solving for X

x = 44.06 g/mol

Therefore, the molar mass of the identified gas is 44.06 g/mol

3 0
4 years ago
What is the product of the unbalanced equation below?
inessss [21]

Answer:

C. HCI(g)

Explanation:

The following equation between hydrogen gas (H2) and oxygen gas (O2) is given below:

H2(g) + Cl2(g) ►

Based on these unbalanced equation, the products of the reaction was not given, however, if one molecule of hydrogen and oxygen combine, hydrogen chloride (HCl) should be produced as the product of the reaction as in:

H2(g) + Cl2(9) ► 2HCl(g)

4 0
3 years ago
How to separate given mixture?
adelina 88 [10]

Answer:

Chromatography involves solvent separation on a solid medium.

Distillation takes advantage of differences in boiling points.

Evaporation removes a liquid from a solution to leave a solid material.

Filtration separates solids of different sizes.

Explanation:

3 0
3 years ago
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